Answer:
the scale drawing of the parallelogram is 2 and 5
Step-by-step explanation:
The computation of the scale drawing of the parallelogram is shown below:
For 6 cm length, it is
= 6 × 1 ÷ 3
= 2
And for 15 cm it is
= 15 × 1 ÷ 3
= 5
Hence, the scale drawing of the parallelogram is 2 and 5
40, because if the ratio is 1:5 then we can times 8 by 5 to get 40 (I think :P)
Answer:
Option A
Step-by-step explanation:
Number of components assembled by the new employee per day,
N(t) = ![\frac{50t}{t+4}](https://tex.z-dn.net/?f=%5Cfrac%7B50t%7D%7Bt%2B4%7D)
Number of components assembled by the experienced employee per day,
E(t) = ![\frac{70t}{t+3}](https://tex.z-dn.net/?f=%5Cfrac%7B70t%7D%7Bt%2B3%7D)
Difference in number of components assembled per day by experienced ane new employee
D(t)= E(t) - N(t)
D(t) = ![\frac{70t}{t+3}-\frac{50t}{t+4}](https://tex.z-dn.net/?f=%5Cfrac%7B70t%7D%7Bt%2B3%7D-%5Cfrac%7B50t%7D%7Bt%2B4%7D)
= ![\frac{70t(t+4)-50t(t+3)}{(t+3)(t+4)}](https://tex.z-dn.net/?f=%5Cfrac%7B70t%28t%2B4%29-50t%28t%2B3%29%7D%7B%28t%2B3%29%28t%2B4%29%7D)
= ![\frac{70t^2+280t-50t^2-150t}{(t+3)(t+4)}](https://tex.z-dn.net/?f=%5Cfrac%7B70t%5E2%2B280t-50t%5E2-150t%7D%7B%28t%2B3%29%28t%2B4%29%7D)
= ![\frac{20t^2+130t}{(t+3)(t+4)}](https://tex.z-dn.net/?f=%5Cfrac%7B20t%5E2%2B130t%7D%7B%28t%2B3%29%28t%2B4%29%7D)
= ![\frac{10t(2t+13)}{(t+4)(t+3)}](https://tex.z-dn.net/?f=%5Cfrac%7B10t%282t%2B13%29%7D%7B%28t%2B4%29%28t%2B3%29%7D)
Therefore, Option A will be the answer.
For the answer to the question above asking the explicit equation and domain for an arithmetic sequence with the first term of 5 and the second term of 2? I think the answer for this is <span>5-2(n-1); all integers where n≥0. I hope this helps.</span>