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zaharov [31]
2 years ago
11

39) Solve the inequality: 4(x+5)≤116 A. x≤−51 B. x≤−40 C. x≤24 D. x≥24

Mathematics
1 answer:
Sever21 [200]2 years ago
3 0

Answer:

x≤24

Step-by-step explanation:

4(x+5)≤116

x+5≤29

x≤29-5

x≤24

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X*2/5=3/20 what si it nowwwwwwwwwwwwwwwwwwwww
gladu [14]

Answer: x = 11/20 = 0.550

Step-by-step explanation:

Rearrange:

Rearrange the equation by subtracting what is to the right of the equal sign from both sides of the equation :

                    x-2/5-(3/20)=0  

Step by step solution :

Step  1  :

            3

Simplify   ——

           20

Equation at the end of step  1  :

       2      3

 (x -  —) -  ——  = 0  

       5     20

Step  2  :

           2

Simplify   —

           5

Equation at the end of step  2  :

       2      3

 (x -  —) -  ——  = 0  

       5     20

Step  3  :

Rewriting the whole as an Equivalent Fraction :

3.1   Subtracting a fraction from a whole

Rewrite the whole as a fraction using  5  as the denominator :

         x     x • 5

    x =  —  =  —————

         1       5  

Equivalent fraction : The fraction thus generated looks different but has the same value as the whole

Common denominator : The equivalent fraction and the other fraction involved in the calculation share the same denominator

Adding fractions that have a common denominator :

3.2       Adding up the two equivalent fractions

Add the two equivalent fractions which now have a common denominator

Combine the numerators together, put the sum or difference over the common denominator then reduce to lowest terms if possible:

x • 5 - (2)     5x - 2

———————————  =  ——————

     5            5    

Equation at the end of step  3  :

 (5x - 2)     3

 ———————— -  ——  = 0  

    5        20

Step  4  :

Calculating the Least Common Multiple :

4.1    Find the Least Common Multiple

     The left denominator is :       5  

     The right denominator is :       20  

       Number of times each prime factor

       appears in the factorization of:

Prime  

Factor   Left  

Denominator   Right  

Denominator   L.C.M = Max  

{Left,Right}  

5 1 1 1

2 0 2 2

Product of all  

Prime Factors  5 20 20

     Least Common Multiple:

     20  

Calculating Multipliers :

4.2    Calculate multipliers for the two fractions

   Denote the Least Common Multiple by  L.C.M  

   Denote the Left Multiplier by  Left_M  

   Denote the Right Multiplier by  Right_M  

   Denote the Left Deniminator by  L_Deno  

   Denote the Right Multiplier by  R_Deno  

  Left_M = L.C.M / L_Deno = 4

  Right_M = L.C.M / R_Deno = 1

Making Equivalent Fractions :

4.3      Rewrite the two fractions into equivalent fractions

Two fractions are called equivalent if they have the same numeric value.

For example :  1/2   and  2/4  are equivalent,  y/(y+1)2   and  (y2+y)/(y+1)3  are equivalent as well.

To calculate equivalent fraction , multiply the Numerator of each fraction, by its respective Multiplier.

  L. Mult. • L. Num.      (5x-2) • 4

  ——————————————————  =   ——————————

        L.C.M                 20    

  R. Mult. • R. Num.       3

  ——————————————————  =   ——

        L.C.M             20

Adding fractions that have a common denominator :

4.4       Adding up the two equivalent fractions

(5x-2) • 4 - (3)     20x - 11

————————————————  =  ————————

       20               20    

Equation at the end of step  4  :

 20x - 11

 ————————  = 0  

    20    

Step  5  :

When a fraction equals zero :

5.1    When a fraction equals zero ...

Where a fraction equals zero, its numerator, the part which is above the fraction line, must equal zero.

Now,to get rid of the denominator, Tiger multiplys both sides of the equation by the denominator.

Here's how:

 20x-11

 —————— • 20 = 0 • 20

   20  

Now, on the left hand side, the  20  cancels out the denominator, while, on the right hand side, zero times anything is still zero.

The equation now takes the shape :

  20x-11  = 0

Solving a Single Variable Equation :

5.2      Solve  :    20x-11 = 0  

Add  11  to both sides of the equation :  

                     20x = 11

Divide both sides of the equation by 20:

                    x = 11/20 = 0.550

One solution was found :

                  x = 11/20 = 0.550

7 0
2 years ago
Please help 6x + 32 = -2x
netineya [11]

Answer: the answer is x=-4.

Step-by-step explanation:

5 0
1 year ago
Which is the most likely first step needed to solve this equation?
Vanyuwa [196]

Answer:

C.  Add 15 to both sides

Step-by-step explanation:

Given equation:

99x – 15 = 45

To solve:

<u>Step 1</u>:  Add 15 to both sides:

⇒ 99x – 15 + 15 = 45 + 15

⇒ 99x = 60

<u>Step 2</u>:  Divide both sides by 99:

⇒ 99x ÷ 99 = 60 ÷ 99

⇒ x = 60/99

⇒ x = 20/33

5 0
2 years ago
Read 2 more answers
To avoid detection at customs, a traveler places 6 narcotic tablets in a bottle containing 9 vitamin tablets that are similar in
lukranit [14]

Answer: \dfrac{26}{27}

Step-by-step explanation:

Given : To avoid detection at customs, a traveler places 6 narcotic tablets in a bottle containing 9 vitamin tablets that are similar in appearance.

Proportion of success : p=\dfrac{6}{9}=\dfrac{2}{3}

Sample size taken by customs official : n= 3

Let x be a binomial variable that represents the tablets in the bottle.

Using Binomial probability formula :-

P(X=x)=^nC_xp^x(1-p)^{n-x}

The probability that the traveler will be arrested for illegal possession of narcotics =P(x\geq1)=1-P(x=0)

1-^3C_0(\dfrac{2}{3})^0(1-\dfrac{2}{3})^3\\\\=1-(1)(1)(\dfrac{1}{3})^3\ [\becuase ^nC_0=1]\\\\=1-\dfrac{1}{27}=\dfrac{26}{27}

Hence, the probability that the traveler will be arrested for illegal possession of narcotics = \dfrac{26}{27}

8 0
3 years ago
5x^2-26x+5 factor the trinomial
ss7ja [257]
The factored form for this question is (5x-1)(x-5)
4 0
3 years ago
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