What’s the equation of a line that is perpendicular to -x +2y =4 and passes through the point (-2,1)
1 answer:
Answer:
y = -2x - 3
Step-by-step explanation:
Given:
Equation of -x +2y =4
Point of (-2,1)
-x + 2y = 4
y = x/2 + 2 or y = 1/2x + 2
Which means the equation's slope is m = 1/2.
The slope of the perpendicular line is negative inverse which is m = -2.
Now we have an equation of y = -2x + a.
Use (-2, 1) to find a:
1 = (-2)(-2) + a
a = -3
y = - 2x - 3
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