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3 years ago

A circle passes through the point (0,0.5). What it’s radius

Mathematics

1 answer:

belka [17]3 years ago

6 0

Answer: The radius of this circle is 0.5

Step-by-step explanation:

We have a circle that passes through the point (0, 0.5)

We do not know the center of the circle, so we have infinite possible radius to answer this, but let's suppose that the center of the circle is in the point (0, 0)

For a circle centered in the origin, we have the equation:

x^2 + y^2 = r^2

Where r is the radius.

Here we have that x = 0 and y = 0.5

then:

0^2 + (0.5)^2 = r^2

0.5^2 = r^2

r = 0.5

The radius of this circle is 0.5

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Together teammates Pedro and Ricky got 2669 base hits last season Pedro had 275 more hits than Ricky how many hits did each play

Readme [11.4K]

Pedro had 1,609.5 and Ricky had 1,074.5.

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3 years ago

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3 years ago

In a school of 330 students, 85 of them are in a drama club, 200 of them are in a sports team and 60 of them do both

Neko [114]

Answer:

105/330 = 21/66 = 7/22

7/22 is the answer I think

Step-by-step explanation:

n(U) = 330

n(A) = 85

n(B) = 200

n(A n B) = 60

Now,

n(A U B) = n(A) + n(B) - n(A n B)

or, n(A U B) = 85 + 200 - 60

or, n(A U B) = 285 - 60 = 225

Now,

n(A U B) compliment = n(U) - n(A U B)

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so, n(A U B) compliment = 105

Now,

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8 0

2 years ago

Selena buys 4 peaches that weigh 1 pound in all. Each peach weigh the same amount. Peaches are on sale for $2.24 per pound. Writ

DENIUS [597]

Answer:

The required equation is

4p = 2.24

And p = 0.56 [ where p is in $]

Step-by-step explanation:

Given that Selena buys 4 peaches that weight 1 pound in all.

Peaches are on sale for $2.24 per pound.

Since the total weight of peaches is 1 pound.

So the price of 4 peaches is $2.24.

Let p be the price of 1 peaches.

Then the price of 4 peaches is $(4×p)

= $4p

According to the problem,

4p = 2.24

$\Rightarrow p=\frac{2.24}{4}$

⇒p=0.56 [ where p is in $]

The required equation is

4p = 2.24

And p = 0.56 [ where p is in $]

8 0

3 years ago

Write an equation for the circle with endpoints of a diameter (9, 4) and (-3, -2)

inysia [295]

If the diameter is at (9,4) and (-3,-2), then the center of the circle is the midpoint of that segment.

and since we know that the radius of a circle is half of the diameter, whatever long that diameter segment is, the radius is half that.

$\bf ~~~~~~~~~~~~\textit{middle point of 2 points }
\\\\
\begin{array}{ccccccccc}
&&x_1&&y_1&&x_2&&y_2\\
% (a,b)
&&(~ 9 &,& 4~) 
% (c,d)
&&(~ -3 &,& -2~)
\end{array}\qquad
% coordinates of midpoint 
\left(\cfrac{ x_2 + x_1}{2}\quad ,\quad \cfrac{ y_2 + y_1}{2} \right)
\\\\\\
\left( \cfrac{-3+9}{2}~~,~~\cfrac{-2+4}{2} \right)\implies \stackrel{center}{(3~,~1)}$

$\bf -------------------------------\\\\
~~~~~~~~~~~~\textit{distance between 2 points}
\\\\
\begin{array}{ccccccccc}
&&x_1&&y_1&&x_2&&y_2\\
% (a,b)
&&(~ 9 &,& 4~) 
% (c,d)
&&(~ -3 &,& -2~)
\end{array}
\\\\\\
d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2}
\\\\\\
d=\sqrt{(-3-9)^2+(-2-4)^2}\implies d=\sqrt{(-12)^2+(-6)^2}
\\\\\\
d=\sqrt{180}\qquad \qquad \qquad radius=\cfrac{\sqrt{180}}{2}$

$\bf -------------------------------\\\\
\textit{equation of a circle}\\\\ 
(x- h)^2+(y- k)^2= r^2
\qquad 
center~~(\stackrel{3}{ h},\stackrel{1}{ k})\qquad \qquad 
radius=\stackrel{\frac{\sqrt{180}}{2}}{ r}
\\\\\\
(x-3)^2+(y-1)^2=\left( \frac{\sqrt{180}}{2} \right)^2\implies (x-3)^2+(y-1)^2=\cfrac{(\sqrt{180})^2}{2^2}
\\\\\\
(x-3)^2+(y-1)^2=\cfrac{180}{4}\implies (x-3)^2+(y-1)^2=45$

7 0

3 years ago