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elixir [45]
3 years ago
9

A circle passes through the point (0,0.5). What it’s radius

Mathematics
1 answer:
belka [17]3 years ago
6 0

Answer: The radius of this circle is 0.5

Step-by-step explanation:

We have a circle that passes through the point (0, 0.5)

We do not know the center of the circle, so we have infinite possible radius to answer this, but let's suppose that the center of the circle is in the point (0, 0)

For a circle centered in the origin, we have the equation:

x^2 + y^2 = r^2

Where r is the radius.

Here we have that x = 0 and y = 0.5

then:

0^2 + (0.5)^2 = r^2

0.5^2 = r^2

r = 0.5

The radius of this circle is 0.5

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kolezko [41]

There will be <u>35 sections</u> for Marjorie to cut from the fabric.

<h3>What is multiplication</h3>

In mathematics, multiplication (denoted by ‘ × ’) is a method of finding the product of two or more values. In arithmetic, multiplication of two numbers represents the repeated addition of one number with respect to another. If m is multiplied by n, then it means either m is added to itself ‘n’ number of times or vice versa.

Given that:

7x=35

7 × 5=35

or \frac{35}{5}=7

Therefore, There will be <u>35 sections</u> for Marjorie to cut from the fabric.

Learn more about multiplication here:

brainly.com/question/14059007

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The current temperature is -7C.The high temperature yesterday was an many degrees about 0C. Which expression could be used to fi
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Solve the system of equations.<br> <img src="https://tex.z-dn.net/?f=%5Cleft%20%5C%7B%20%7B%7By%3D220x-160%7D%20%5Catop%20%7By%3
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\begin{cases} y=220x-160\\ y=20x^2-400 \end{cases}\qquad \qquad \stackrel{\textit{substituting on the 2nd equation}}{\stackrel{\textit{\Large y}}{220x-160}~~ = ~~20x^2-400} \\\\\\ -160=20x^2-220x-400\implies 0=20x^2-220x-240 \\\\\\ 0=20(x^2-11x-12)\implies 0=x^2-11x-12 \\\\\\ 0=(x-12)(x+1)\implies x= \begin{cases} 12\\ -1 \end{cases}

\dotfill\\\\ x=12\qquad \qquad \stackrel{\textit{substituting on the 1st equation}}{y=220(12)-160}\implies y=2480 \\\\\\ x=-1\qquad \qquad \stackrel{\textit{substituting on the 1st equation}}{y=220(-1)-160}\implies y=-380 \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ ~\hfill (12~~,~~2480)\qquad (-1~~,~~-380)~\hfill

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2 years ago
How do you solve 10+5(3x-4)=2x+7
Taya2010 [7]

Answer:

x=1\dfrac{4}{13}

Step-by-step explanation:

Given the equation

10+5(3x-4)=2x+7

Use distributive property:

10+5\cdot 3x-5\cdot 4=2x+7\\ \\10+15x-20=2x+7

Use commutative property to rewrite the equation:

15x+10-20=2x+7

15x-10=2x+7

Add 10 th both sides:

15x-10+10=2x+7+10\\ \\15x=2x+17

Subtract 2x:

15x-2x=2x+17-2x\\ \\13x=17

Divide by 13:

x=\dfrac{17}{13}=1\dfrac{4}{13}

4 0
4 years ago
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