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Evgesh-ka [11]
2 years ago
5

Movie tickets cost $36. At this rate what is the cost per ticket? $

Mathematics
1 answer:
oee [108]2 years ago
5 0

Answer:

$11,679,552   my brother said this

Step-by-step explanation:

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Estimate the perimeter and area of the shaded figure to the nearest tenth.
Maru [420]

Answer:

Perimeter = 18.7 units

Area = 13.5 units²

Step-by-step explanation:

Perimeter of ADEC = AD + DE + EC + AC

Length of AD = 3 units

By applying Pythagoras theorem in ΔDBE,

DE² = DB² + BE²

DE² = 3² + 3²

DE = √18

DE = 4.24 units

Length of EC = 3 units

By applying Pythagoras theorem in ΔABC,

AC² = AB² + BC²

AC² = 6² + 6²

AC = √72

AC = 8.49 units

Perimeter of ADEC = 3 + 4.24 + 3 + 8.49

                                 = 18.73 units

                                 ≈ 18.7 units

Area of ADEC = Area of ΔABC - Area of ΔBDE

Area of ΔABC = \frac{1}{2}(AB)(BC)

                       = \frac{1}{2}(6)(6)

                       = 18 units²

Area of ΔBDE = \frac{1}{2}(BD)(BE)

                       = \frac{1}{2}(3)(3)

                       = 4.5 units²

Area of ADEC = 18 - 4.5

                        = 13.5 units²

6 0
3 years ago
For every 7 glasses wearers in a Classroom,there are about 13 non glasses wearers.If there are 32 students in a entire class how
Alla [95]

Answer:

21 With glasses

Step-by-step explanation:

32/20=1.6

1.6•7=11.2 Without Glasses

1.6•13=20.8 With Glasses

20.8 rounded to nearest whole number=21

6 0
3 years ago
Please i need to get good grades
daser333 [38]

Answer:

47°

Step-by-step explanation:

angles x and 133 are supplementary, so they add up to 180°

subtract 133 from 180 to get 47

7 0
3 years ago
What’s 5 4/9 as an improper fraction
strojnjashka [21]

Answer: 49/9

Step-by-step explanation:

9x5=45

45+4=49

8 0
3 years ago
Let R be the shaded region in the first quadrant enclosed by the y-axis and the graphs of y=sinx and y=cosx.
julsineya [31]
<span>since sin and cos = each other at pi/4; take your integrals from 0 to pi/4
</span><span>[S] cos(t) dt - [S] sin(t) dt ;[0,pi/4]
</span>
<span>to revolve it around the x axis;
we do a sum of areas [S] 2pi [f(x)]^2 dx
</span>
<span>take the cos first and subtract out the sin next; like cutting a hole out of a donuts.
</span><span>pi [S] cos(x)^2 dx - [S] sin(x)^2 dx ; [0,pi/4]
</span>
<span>cos(2t) = 2cos^2 - 1
cos^2 = (1+cos(2t))/2
</span>
<span>1/sqrt(2) - (-1/sqrt(2) +1)
1/sqrt(2) + 1/sqrt(2) -1
(2sqrt(2) - sqrt(2))/sqrt(2) = sqrt(2)/sqrt(2) = 1</span>
3 0
3 years ago
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