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brilliants [131]

3 years ago

5

Suppose you have $12,000 to invest. If part is invested at 10% and the rest at 15%, how much should be invested at each rate to

yield 12% on the total amount invested?

1 answer:

Ivahew [28]3 years ago

3 0

X=invested at 10%12000-x=invested at 15% .10x+ (.15)(12000-x)=1440 ;; 12% of the total amount is 12% of $12000. .10x + 1800-.15x=1440
-0.05x=-360x=7200 12000-x=4800 $7200 at 10%=$720$4800 at 15%=$720 That is $12000 earning $1440, and that is 12%

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Write the equation of the quadratic function in standard form represented by the graph

Nutka1998 [239]

Hello :
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3 0

3 years ago

Which correctly describes how the graph of the inequality 6y − 3x > 9 is shaded? -Above the solid line

baherus [9]

The statement which correctly describes the shaded region for the inequality is $\fbox{\begin\\\ Above the dashed line\\\end{minispace}}$

Further explanation:

In the question it is given that the inequality is $6y-3x>9$ .

The equation corresponding to the inequality $6y-3x>9$ is $6y-3x=9$ .

The equation $6y-3x=9$ represents a line and the inequality $6y-3x>9$ represents the region which lies either above or below the line $6y-3x=9$ .

Transform the equation $6y-3x=9$ in its slope intercept form as $y=mx+c$ , where $m$ represents the slope of the line and $c$ represents the $y$ -intercept.

$y$ -intercept is the point at which the line intersects the $y$ -axis.

In order to convert the equation $6y-3x=9$ in its slope intercept form add $3x$ to equation $6y-3x=9$ .

$6y-3x+3x=9+3x$

$6y=9+3x$

Now, divide the above equation by $6$ .

$\fbox{\begin\\\math{y=\dfrac{x}{2}+\dfrac{1}{2}}\\\end{minispace}}$

Compare the above final equation with the general form of the slope intercept form $\fbox{\begin\\\math{y=mx+c}\\\end{minispace}}$ .

It is observed that the value of $m$ is $\dfrac{1}{2}$ and the value of $c$ is $\dfrac{3}{2}$ .

This implies that the $y$ -intercept of the line is $\dfrac{3}{2}$ so, it can be said that the line passes through the point $\fbox{\begin\\\ \left(0,\dfrac{3}{2}\right)\\\end{minispace}}$ .

To draw a line we require at least two points through which the line passes so, in order to obtain the other point substitute $0$ for $y$ in $6y=9+3x$ .

$0=9+3x$

$3x=-9$

$\fbox{\begin\\\math{x=-3}\\\end{minispace}}$

This implies that the line passes through the point $\fbox{\begin\\\ (-3,0)\\\end{minispace}}$ .

Now plot the points $(-3,0)$ and $\left(0,\dfrac{3}{2}\right)$ in the Cartesian plane and join the points to obtain the graph of the line $6y-3x=9$ .

Figure $1$ shows the graph of the equation $6y-3x=9$ .

Now to obtain the region of the inequality $6y-3x>9$ consider any point which lies below the line $6y-3x=9$ .

Consider $(0,0)$ to check if it satisfies the inequality $6y-3x>9$ .

Substitute $x=0$ and $y=0$ in $6y-3x>9$ .

$(6\times0)-(3\times0)>9$

$0>9$

The above result obtain is not true as $0$ is not greater than $9$ so, the point $(0,0)$ does not satisfies the inequality $6y-3x>9$ .

Now consider $(-2,2)$ to check if it satisfies the inequality $6y-3x>9$ .

Substitute $x=-2$ and $y=2$ in the inequality $6y-3x>9$ .

$(6\times2)-(3\times(-2))>9$

$12+6>9$

$18>9$

The result obtain is true as $18$ is greater than $9$ so, the point $(-2,2)$ satisfies the inequality $6y-3x>9$ .

The point $(-2,2)$ lies above the line so, the region for the inequality $6y-3x>9$ is the region above the line $6y-3x=9$ .

The region the for the inequality $6y-3x>9$ does not include the points on the line $6y-3x=9$ because in the given inequality the inequality sign used is $>$ .

Figure $2$ shows the region for the inequality $\fbox{\begin\\\math{6y-3x>9}\\\end{minispace}}$ .

Therefore, the statement which correctly describes the shaded region for the inequality is $\fbox{\begin\\\ Above the dashed line\\\end{minispace}}$

Learn more:

A problem to determine the range of a function brainly.com/question/3852778
A problem to determine the vertex of a curve brainly.com/question/1286775
A problem to convert degree into radians brainly.com/question/3161884

Answer details:

Grade: High school

Subject: Mathematics

Chapter: Linear inequality

Keywords: Linear, equality, inequality, linear inequality, region, shaded region, common region, above the dashed line, graph, graph of inequality, slope, intercepts, y-intercept, 6y-3x=9, 6y-3x>9, slope intercept form.

4 0

3 years ago

Read 2 more answers

16 students are percussionist which is 20% of the students how many students are in band

11Alexandr11 [23.1K]

Answer:

80 Students are in the band class

Step-by-step explanation:

I did this mentally so sorry if it is bad

16 = 20%

+

16 = 20%

= 40% 32 students

40% +40% = 80%

32+ 32 = 64

80+20%

64+16

80 Students are in the band class

5 0

3 years ago

The area of a rectangle is 1176 square meters. The width of the rectangle is 21 meters. What i the length of the rectangle?

stepan [7]

Answer:

56

Step-by-step explanation:

1176 divided by 21 = 56

3 0

3 years ago

Given that a 90% confidence interval for the mean height of all adult males in Idaho measured in inches was [62.532, 76.478]. Wh

NNADVOKAT [17]

Answer:

The point estimate used to estimate the mean height of all adult males in Idaho is 69.505 inches.

Step-by-step explanation:

Each confidence interval has two bounds, the lower bound and the upper bound. The points estimate used to estimate the mean is the halfway point between those two bounds, that is, the sum of those two bounds divided by two.

In this problem, we have that:

Lower bound: 62.532

Upper bound: 76.478

Point estimate: (62.532 + 76.478)/2 = 69.505

The point estimate used to estimate the mean height of all adult males in Idaho is 69.505 inches.

3 0

3 years ago