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dimulka [17.4K]
3 years ago
6

I need help with this ASAP plzzzzz

Mathematics
1 answer:
miss Akunina [59]3 years ago
5 0

Answer:

23. \frac{4\sqrt{3} }{3}

24. \frac{7\sqrt{3}}{3}

25. 6\sqrt{3}

26. \frac{10\sqrt{3} }{3}

27.  14

28. 4\sqrt{3}

Step-by-step explanation:

To solve these i used SOHCAHTOA

sin=\frac{opposite}{adjacent}\\ cos=\frac{adjacent}{hypotenuse} \\tan=\frac{opposite}{adjacent}

23.

Find the missing side using Tangent

tan(30)=\frac{x}{4}

4*tan(30)=x

\frac{4\sqrt{3} }{3}

24.

Find the missing side using Tangent

tan(30)=\frac{x}{7}

7*tan(30)=x

\frac{7\sqrt{3}}{3}

25.

Find the missing side using Tangent

tan(30)=\frac{x}{18}

18*tan(30)=x

6\sqrt{3}

26.

Find the missing side using Tangent

tan(30)=\frac{x}{10}

10*tan(30)=x

\frac{10\sqrt{3} }{3}

27.

Find the missing side using Tangent

tan(30)=\frac{x}{14\sqrt{3} }

(14\sqrt{3}) *tan(30)=x

14

28.

Find the missing side using Tangent

tan(30)=\frac{x}{12}

12*tan(30)=x

4\sqrt{3}

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The LCM of the denominators is 120. In other words, the denominators can multiply to 120.

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Answer

Tigers: P = 80/120

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A diver descends to a location of -50 1 over 4 meters relative to the surface of the water. He then descends another 10 1 over 2
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Answer:

-60\frac{3}{4} meters.

Step-by-step explanation:

To find diver's final location relative to the surface of water we will subtract  10\frac{1}{2} from -50\frac{1}{4} because diver dives away another 10\frac{1}{2} from his previous location of -50\frac{1}{4}.

-50\frac{1}{4} -10\frac{1}{2}

Now we will convert our mixed fraction into improper fraction and then we will find a common denominator.

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Now let us convert our answer in mixed fraction.

=\frac{-243}{4}=[tex]-60\frac{3}{4}[/tex]

Therefore, diver's final location relative to the surface of the water is -60\frac{3}{4} meters.

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3 years ago
Read 2 more answers
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