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dimulka [17.4K]
4 years ago
6

I need help with this ASAP plzzzzz

Mathematics
1 answer:
miss Akunina [59]4 years ago
5 0

Answer:

23. \frac{4\sqrt{3} }{3}

24. \frac{7\sqrt{3}}{3}

25. 6\sqrt{3}

26. \frac{10\sqrt{3} }{3}

27.  14

28. 4\sqrt{3}

Step-by-step explanation:

To solve these i used SOHCAHTOA

sin=\frac{opposite}{adjacent}\\ cos=\frac{adjacent}{hypotenuse} \\tan=\frac{opposite}{adjacent}

23.

Find the missing side using Tangent

tan(30)=\frac{x}{4}

4*tan(30)=x

\frac{4\sqrt{3} }{3}

24.

Find the missing side using Tangent

tan(30)=\frac{x}{7}

7*tan(30)=x

\frac{7\sqrt{3}}{3}

25.

Find the missing side using Tangent

tan(30)=\frac{x}{18}

18*tan(30)=x

6\sqrt{3}

26.

Find the missing side using Tangent

tan(30)=\frac{x}{10}

10*tan(30)=x

\frac{10\sqrt{3} }{3}

27.

Find the missing side using Tangent

tan(30)=\frac{x}{14\sqrt{3} }

(14\sqrt{3}) *tan(30)=x

14

28.

Find the missing side using Tangent

tan(30)=\frac{x}{12}

12*tan(30)=x

4\sqrt{3}

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