Y=3/4x-3
Plot -3 on the y axis then go up 3 and right 4
Right scalene triangle is formed for given side lengths
1. 8apples=3 3/4
24apples=8apples ×3=15/4×3
=45/4 0r 11 3/4 or 11.25
Answer:
Step-by-step explanation:
![a^{m}*a^{n}=a^{m+n}\\\\](https://tex.z-dn.net/?f=a%5E%7Bm%7D%2Aa%5E%7Bn%7D%3Da%5E%7Bm%2Bn%7D%5C%5C%5C%5C)
![a) 3x^{2}y^{4}*2x^{6}y=3*2*x^{2+6}*y^{4+1}\\\\=6x^{8}y^{5}](https://tex.z-dn.net/?f=a%29%203x%5E%7B2%7Dy%5E%7B4%7D%2A2x%5E%7B6%7Dy%3D3%2A2%2Ax%5E%7B2%2B6%7D%2Ay%5E%7B4%2B1%7D%5C%5C%5C%5C%3D6x%5E%7B8%7Dy%5E%7B5%7D)
![b) xz^{3} * 4x^{4}z^{5}=4*x^{1+4}*z^{3+5}\\\\= 4x^{5}z^{8}](https://tex.z-dn.net/?f=b%29%20xz%5E%7B3%7D%20%2A%204x%5E%7B4%7Dz%5E%7B5%7D%3D4%2Ax%5E%7B1%2B4%7D%2Az%5E%7B3%2B5%7D%5C%5C%5C%5C%3D%204x%5E%7B5%7Dz%5E%7B8%7D)
c)
![4a^{3}b^{2}* 3a^{6}b^{5}=4*3*a^{3+6}*b^{2+5}\\\\=12a^{9}b^{7}](https://tex.z-dn.net/?f=4a%5E%7B3%7Db%5E%7B2%7D%2A%203a%5E%7B6%7Db%5E%7B5%7D%3D4%2A3%2Aa%5E%7B3%2B6%7D%2Ab%5E%7B2%2B5%7D%5C%5C%5C%5C%3D12a%5E%7B9%7Db%5E%7B7%7D)
![d) 6s^{5}t*s^{4}t^{2}=6*s^{5+4}*t^{1+2}\\\\=6s^{9}t^{3}\\](https://tex.z-dn.net/?f=d%29%206s%5E%7B5%7Dt%2As%5E%7B4%7Dt%5E%7B2%7D%3D6%2As%5E%7B5%2B4%7D%2At%5E%7B1%2B2%7D%5C%5C%5C%5C%3D6s%5E%7B9%7Dt%5E%7B3%7D%5C%5C)
Answer:
The probability that the middle school student owns a skateboard or a bicycle is 0.61.
Step-by-step explanation:
We are given that the probability of a middle school student owning a skateboard is 0.58, of owning a bicycle is 0.48, and owning both is 0.45.
A middle school student is chosen at random.
Let the probability of student owning a skateboard = P(S) = 0.58
The probability of student owning a bicycle = P(B) = 0.48
The probability of student owning both = P(S
B) = 0.45
Now, the probability that the middle school student owns a skateboard or a bicycle is given by = P(S
B)
P(S
B) = P(S) + P(B) - P(S
B)
= 0.58 + 0.48 - 0.45
= 0.61
Hence, the probability that the middle school student owns a skateboard or a bicycle is 0.61.