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meriva
3 years ago
8

I need urgent help with this one

Mathematics
2 answers:
dolphi86 [110]3 years ago
6 0

Answer:

0.6

Step-by-step explanation:

-1 1/2 + 2.1 = 0.6

Serhud [2]3 years ago
5 0

let the unknown answer be equal to f

.-2.1 - f = -3/2

-f = -3/2 + 2.1

-f = 0.6

f = -0.6

You might be interested in
The distance between B and C
alina1380 [7]

Answer:

The answer is

<h2>\sqrt{13}  \:  \: or \:  \: 3.6055 \:  \: units</h2>

Step-by-step explanation:

The distance between two points can be found by using the formula

d =  \sqrt{( {x1 - x2})^{2} +  ({y1 - y2})^{2}  }  \\

where

(x1 , y1) and (x2 , y2) are the points

From the question the points are

B ( 3 , 1 ) and C( 6 , 3)

The distance between them is

|BC|  =  \sqrt{( {3 - 6})^{2}  +  ({1 - 3})^{2} }  \\  =  \sqrt{ ({ - 3})^{2}  + ( { - 2})^{2} }  \\  =  \sqrt{9 + 4}

We have the final answer as

\sqrt{13}  \:  \: or \:  \: 3.6055 \:  \: units

Hope this helps you

5 0
3 years ago
Consider the spreading of a rumor through a company of 1000 employees, allworking in the same building.We assume that the spread
natima [27]

Answer:

On the 12th day, the rumor would have has to all the 1000 employees

Step-by-step explanation:

Given the data in the question;

so, lets consider the rumor spreading thorough the company of 1000 employee;

the given model is; r_{n+1} = r_{n} + 1000kr_{n} ( 1000 - r_{n} )

where k is the parameter that depends on how fast the rumor spreads, n is the number of days.

now, lets assume k = 0.0001, lets also assume r₀ = 4

so to find how soon all 1000 employees  will have heard the rumor  ;

let n be;

then r1 will be;

r1 = r₀ + ( 0.001)r₀(1000-r₀ )

so

r1 = 4 + ( 0.001) × 4× (1000 - 4 )

r1 = 7.984

r2 will be;

r2 = r1 + ( 0.001)r1(1000-r1 )

r2 =  7.984 + ( 0.001) × 7.984 × (1000 - 7.984 )

r2 = 15.904255744

   

r3  will be;

r3 = r2 + ( 0.001)r2(1000-r2 )  

r3 = 15.904255744 + ( 0.001) × 15.904255744 × (1000 - 15.904255744 )

r3 = 31.555566137

Using the same formula and procedure by substituting n = 1,2,3,4,5,6,7,8,9,10,11,12.

we will have;

n        rₙ

0        4

1        7.984

2       15.904255744

3       31.555566137

4       62.1153785

5       120.372437

6       226.25535

7       401.319217

8       641.58132

9       871.53605

10     983.497013

11      999.727651

12     999.999926

Therefore, On the 12th day, the rumor would have has to all the 1000 employees

 

5 0
3 years ago
Which shows one way to determine the factors of y3 – 9x2 + 5x – 45 by grouping
Gnoma [55]

Answer:

(x²+5)(x-9)

Step-by-step explanation:

Assuming that you are asking to factor by grouping:

x³ - 9x² + 5x – 45

You can group:

x²(x-9) + 5(x-9)

and then combine the x² and 5:

(x²+5)(x-9)

4 0
3 years ago
If you know this pls help ):
Aleksandr-060686 [28]
From the right hand side, we will need to find a way to rewriting 3x²y in terms of cube roots.
We know that 27 is 3³, so if we were to rewrite it in terms of cube roots, we will need to multiply everything by itself two more twice. (ie we can rewrite it as ∛(3x²y)³)

Hence, we can say that it's:
 \sqrt[3]{162x^{c}y^{5}} = \sqrt[3]{(3x^{2}y)^{3}} * \sqrt[3]{6y^{d}}
= \sqrt[3]{162x^{6}y^{3+d}}

Hence, c = 6 and d = 2
4 0
3 years ago
A pet store holds training classes for dogs. The store has two different training programs. The first program charges a $35 memb
GrogVix [38]

The programs cost the same for 7 classes.

Given, no. of classes is represented by c, no. of dogs is represented by d, no. of hours is represented by h, the no. of programs is represented by p and the total cost is represented by t.

The first program charges $35 membership fee and $5 for each class.

The second program charges only $10 for each class.

Now the total cost say t_{1}, for first program can be written in equation form as,

t_{1} =35+5c,  here c is the no. of classes.

Similarly, the total cost say t_{2} , for second program can be written in equation form as,

t_{2} =10c.

We have to find out the no. of classes for which the two programs cost the same.

according to the question,

t_{1} =t_{2}

35+5c=10c\\10c-5c=35\\5c=35\\c=7

Hence for 7 of classes the programs cost the same.

For more details follow the link:

brainly.com/question/4042361

3 0
2 years ago
Read 2 more answers
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