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2 years ago

The sum of two positive numbers is 16 and their difference is 2 . the larger number is?

Mathematics

2 answers:

Aleonysh [2.5K]2 years ago

8 0

Answer:

Step-by-step explanation:

7 + 9 = 16

9 - 7 = 2

The larger number is 9

Hope that helps!

irakobra [83]2 years ago

6 0

Answer: $9$

Step-by-step Explanation: $9+7=16$ and $9-7=2$ and $9$ is bigger so the answer is $9$ .

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Find the prime factors of 60 by dividing by prime numbers.

Mars2501 [29]

Let's start with the smallest prime number 2

60/2 = 30

Divide that result over 2

30/2 = 15

We can't divide this by 2 because 15/2 = 7.5 isn't a whole number

Let's move onto 3

15/3 = 5

The result is a prime number, so we stop.

The values we divided as denominators were: {2, 2, 3}

We add the result 5 to the set to completely list all of the prime factors of 60

The prime factorization would be

which is the same as saying

7 0

2 years ago

8x - 8 - x = 3 (6 - 2x)

Ksivusya [100]

Answer:

x = 2

Step-by-step explanation:

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)

{\color{#c92786}{8x}}-8{\color{#c92786}{-x}}=3(6-2x)

8x−8−x=3(6−2x)

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−

)

7 0

2 years ago

12/18 reduced to the lowest term

melomori [17]

2/3 is it's simplified form

8 0

2 years ago

If there's a sale and the original price is 140 and it's one fifth off how much is the sale?

Alex777 [14]

$112
1-1/5=4/5
4/5 x 140 =112
hope this helps :)

6 0

2 years ago

Grasshoppers are distributed at random in a large field according to a Poisson process with parameter a 5 2 per square yard. How

HACTEHA [7]

In this question, the Poisson distribution is used.

Poisson distribution:

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

$P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}$

In which

x is the number of sucesses

e = 2.71828 is the Euler number

$\mu$ is the mean in the given interval.

Parameter of 5.2 per square yard:

This means that $\mu = 5.2r$ , in which r is the radius.

How large should the radius R of a circular sampling region be taken so that the probability of finding at least one in the region equals 0.99?

We want:

$P(X \geq 1) = 1 - P(X = 0) = 0.99$

Thus:

$P(X = 0) = 1 - 0.99 = 0.01$

We have that:

$P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}$

$P(X = 0) = \frac{e^{-5.2r}*(5.2r)^{0}}{(0)!} = e^{-5.2r}$

Then

$e^{-5.2r} = 0.01$

$\ln{e^{-5.2r}} = \ln{0.01}$

$-5.2r = \ln{0.01}$

$r = -\frac{\ln{0.01}}{5.2}$

$r = 0.89$

Thus, the radius should be of at least 0.89.

Another example of a Poisson distribution is found at brainly.com/question/24098004

3 0

2 years ago

The sum of two positive numbers is 16 and their difference is 2 . the larger number is?​

The sum of two positive numbers is 16 and their difference is 2 . the larger number is?