Answer:
<h2>This equation has no natural roots.</h2>
Step-by-step explanation:

Answer: Hey the answer is f(x)=4•(0.5)^x
Step-by-step explanation:
Answer:

Step-by-step explanation:
We are given that Ben has a cell phone plan that provides 200 free minutes each month for a flat rate of $39.
We are also told that For any minutes over 200, Ben is charged $0.35 per minute.
let x be the minutes used each month
So, if 
So, coat will be $39
If 
So, Ben is charged $0.35 per minute
So, when 
So, charge = 
So, the piecewise functions accurately represents charges based on Ben's cell phone :

Multiply the number outside the parenthesis by each term inside the parenthesis:
2(v+5) = 2v + 10