What is the value of X (x+40) (3x)

Add 12 to me. Then add another 12. If you subtract 9 and then add 7, you get 24. What number am I?

tiny-mole [99]

Answer:

2

Step-by-step explanation:

x+12+12-9+7 = 24

x+22 = 24

x = 2

4 0

3 years ago

Factor the expression. 10g^3 12g^2 – 15g – 18

Tanya [424]

10g^3 + 12g^2 - 15g - 18 = 2g^2(5g + 6) - 3(5g + 6) = (2g^2 - 3)(5g + 6)

3 0

3 years ago

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Worth 25 points!

MrRissso [65]

Answer:

1) $\sqrt{-48}=4\sqrt{3} \ i$

2) $\sqrt{-63}=3\sqrt{7} \ i$

3) $\sqrt{-72}=6\sqrt{2} \ i$

4) $\sqrt{-24}=4\sqrt{6} \ i$

5) $\sqrt{-84}=2\sqrt{21} \ i$

6) $\sqrt{-99}=3\sqrt{11} \ i$

Step-by-step explanation:

We need to simply the following :

Note: For all questions given we know that $\sqrt{-1}=i$ using it in all the given questions.

1) $\sqrt{-48}$

Factors of 48 are: 2x2x2x2x3

$\sqrt{-48}\\=\sqrt{48}\sqrt{-1} \\=\sqrt{2\times2\times2\times2\times3}\ i\\= \sqrt{2^2\times2^2\times3}\ i\\=2\times2\sqrt{3} \ i \\=4\sqrt{3} \ i$

2) $\sqrt{-63}$

Factors of 63 are: 3x3x7

$\sqrt{-63}\\=\sqrt{63}\sqrt{-1} \\=\sqrt{3\times3\times7}\ i\\= \sqrt{3^2\times7}\ i\\=3\sqrt{7} \ i$

3) $\sqrt{-72}$

Factors of 72 are: 2x2x2x3x3

$\sqrt{-72}\\=\sqrt{72}\sqrt{-1} \\=\sqrt{2\times2\times2\times3\times3}\ i\\= \sqrt{2^2\times3^2\times2}\ i\\=2\times3\sqrt{2} \ i \\=6\sqrt{2} \ i$

4) $\sqrt{-24}$

Factors of 24 are: 2x2x2x3

$\sqrt{-24}\\=\sqrt{24}\sqrt{-1} \\=\sqrt{2\times2\times2\times3}\ i\\= \sqrt{2^2\times2\times3}\ i\\=2\sqrt{2\times3} \ i \\=2\sqrt{6} \ i$

5) $\sqrt{-84}$

Factors of 84 are: 2x2x3x7

$\sqrt{-84}\\=\sqrt{84}\sqrt{-1} \\=\sqrt{2\times2\times3\times7}\ i\\= \sqrt{2^2\times3\times7}\ i\\=2\sqrt{21} \ i$

6) $\sqrt{-99}\\$

Prime factors of 99 are: 3x3x11

$\sqrt{-99}\\=\sqrt{99}\sqrt{-1} \\=\sqrt{3\times3\times11}\ i\\= \sqrt{3^2\times11}\ i\\=3\sqrt{11} \ i \\=3\sqrt{11} \ i$

6 0

3 years ago

Use the function f(x) = −16x^2 + 22x + 3 to answer the questions.

vaieri [72.5K]

Answer:

see below

Step-by-step explanation:

f(x) = −16x^2 + 22x + 3

Factor out the negative

f(x) = -( 16x^2 -22x -3)

= -(8x+1)(2x-3)

Find the x intercepts

Set y = 0

0 = -(8x+1)(2x-3)

Using the zero product property

8x+1 =0 2x-3 = 0

8x = -1 2x = 3

x = -1/8 x =3/2

The x intercepts are ( -1/8, 0) and ( 3/2, 0)

The end behavior

-16 x^2 is the dominate term

Let x →-∞

f(-∞) = -16 (-∞)^2 = -16 (∞) = -∞

As x goes to negative infinity y goes to - infinity

Let x →∞

f(∞) = -16 (∞)^2 = -16 (∞) = -∞

As x goes to infinity y goes to - infinity

We know this is a downward facing parabola a < 0 and this is a quadratic

We have the x intercepts

We can find the axis of symmetry from the zeros

(-1/8+ 3/2) /2 = (-1/8 + 12/8)/2 = (11/8)/2 = 11/6

The axis of symmetry is x = 11/16

Using the axis of symmetry and the equation, we can find the maximum point

y = -(8*11/16+1)(2*11/16-3) = 169/16

The vertex is at (11/16, 169/16(

7 0

3 years ago

Зm — 5n = 11 what is this answer?

Ainat [17]

It’s -11/2 or M= -5.5

6 0

3 years ago

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