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2 years ago

15

Find the value of the expression below if x=10. x2−2(x+5)PLZ HELP GIVING BRANLIEST

1 answer:

DiKsa [7]2 years ago

5 0

-10

Step-by-step explanation:

x = 10

x2 - 2(x + 5)

10(2) - 2(10+5)

20 - 2(15)

20 - 30

-10

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What similarity statement can you write relating the three triangles in the diagram?

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Answer:

They are both right-angled triangles.

Step-by-step explanation:

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1 year ago

When Mrs. Stewart makes pie dough, she uses 2/3 cup of shortening for every 2 1/2 cups of flour which proportion could be used t

zloy xaker [14]

Answer:

The amount of flour Mrs.Stewart needs for 5 cups of shortening $=\frac{75}{4} =18\tfrac{3}{4}$ cups.

Step-by-step explanation:

Mrs.Stewart pie dough needs $\frac{2}{3}$ cups of shortening for $2\tfrac{1}{2}=\frac{5}{2}$ cups of flour.

Now we assume that the shortening needed for $x$ cups of flour is $y$ cups.

Accordingly we can arrange the ratios.

So for one cup of shortening how many cups of flour is needed we have to use the unitary method:

$\frac{cups\ of flour\ (x)}{cups\ of\ shortening\ (y)} =\frac{x}{y} =\frac{5/2}{2/3}$

Plugging the value of $y=5$ as it is number of cups of shortening Mrs.Stewart have used.

And multiplying both sides with $5$ .

Number of cups of flour needed when $5$ cups of shortenings are used $(x) =\frac{x}{y} =\frac{5/2}{2/3}$ .

So, $(x)=\frac{5\times 3\times 5}{2\times 2} =\frac{75}{4} = 18\tfrac{3}{4}$

The amount of floor Mrs.Stewart needed for $5$ cups of shortening $= 18\tfrac{3}{4}\$ cups of floor.

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2 years ago

(Geometry Question) : Given the points A(-3, -4) and B(2, 0), find the coordinates of the point P on directed line segment AB th

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Read 2 more answers

Water is added to a cylindrical tank of radius 5 m and height of 10 m at a rate of 100 L/min. Find the rate of change of the wat

nirvana33 [79]

Answer:

$V = \pi r^2 h$

For this case we know that $r=5m$ represent the radius, $h = 10m$ the height and the rate given is:

$\frac{dV}{dt}= \frac{100 L}{min}$

$Q = 100 \frac{L}{min} *\frac{1m^3}{1000L}= 0.1 \frac{m^3}{min}$

And replacing we got:

$\frac{dh}{dt}=\frac{0.1 m^3/min}{\pi (5m)^2}= 0.0012732 \frac{m}{min}$

And that represent $0.127 \frac{cm}{min}$

Step-by-step explanation:

For a tank similar to a cylinder the volume is given by:

$V = \pi r^2 h$

For this case we know that $r=5m$ represent the radius, $h = 10m$ the height and the rate given is:

$\frac{dV}{dt}= \frac{100 L}{min}$

For this case we want to find the rate of change of the water level when h =6m so then we can derivate the formula for the volume and we got:

$\frac{dV}{dt}= \pi r^2 \frac{dh}{dt}$

And solving for $\frac{dh}{dt}$ we got:

$\frac{dh}{dt}= \frac{\frac{dV}{dt}}{\pi r^2}$

We need to convert the rate given into m^3/min and we got:

$Q = 100 \frac{L}{min} *\frac{1m^3}{1000L}= 0.1 \frac{m^3}{min}$

And replacing we got:

$\frac{dh}{dt}=\frac{0.1 m^3/min}{\pi (5m)^2}= 0.0012732 \frac{m}{min}$

And that represent $0.127 \frac{cm}{min}$

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Which inequality best represents the situation in which you must be at least 42 inches tall to ride the roller coaster

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