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andriy [413]
3 years ago
8

What is value of this expression below when y=3 8y^2-y-8

Mathematics
2 answers:
serg [7]3 years ago
8 0
Plug in 3 for y
8(3)^2-(3)-8
8(9)-3-8
72-3-8 = 61
VMariaS [17]3 years ago
8 0

Answer:

61

Step-by-step explanation:

8x3^2 -3-8

8x9-3-8

72-3-8

72-11

61

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How many coefficients are in 5z squared +16
Viktor [21]
5z^2 + 16

a coefficient is a number multiplied by a variable (a letter). so there is only ONE coefficient in this expression and it is 5.
3 0
3 years ago
Merchandise is ordered on November 10; the merchandise is shipped by the seller and the invoice is prepared, dated, and mailed b
natali 33 [55]

Answer:

November 13

Step-by-step explanation:

Following dates are given

On November 10 = Merchandise ordered

Date of an invoice prepared, dated and mailed = November 13

Date when the merchandised received by the buyer = November 18

So, the credit period begins when the invoice is prepared, dated and the mailed by the seller to the buyer as it is the evidence of that the merchandise is ordered            

4 0
3 years ago
Can someone help me with this. ^_^ THANKS
Fynjy0 [20]
It would be B. because it's just 7 times 1.5
4 0
3 years ago
A car starts with a dull tank of gas. After driving around 5he city, 1/7 of the gas has been used. With the rest of the gas in t
Sati [7]

Answer:

\frac{2}{7}

Step-by-step explanation:

Given:

A car starts with a dull tank of gas

1/7 of the gas has been used around the city.

With the rest of the gas in the car, the car can travel to and from Ottawa three times.

Question asked:

What fractions of a tank of gas does each complete trip to Ottawa use?

Solution:

Fuel used around the city = \frac{1}{7}

Remaining fuel after driving around the city = 1 - \frac{1}{7}

                                                                         =    \frac{7 - 1}{7}  = \frac{6}{7}

According to question:

As from the rest of the gas in the car that is \frac{6}{7}, the car can complete 3 trip to Ottawa  which means,

By unitary method:

The car can complete 3 trip by using = \frac{6}{7} tank of gas.

The car can complete 1 trip by using =  \frac{6}{7} \div 3

                                                             =\frac{6}{7} \times\frac{1}{3}

                                                             =  \frac{6}{21}

                                                             = \frac{2}{7} tank of gas

Thus, \frac{2}{7} tank of gas used for each complete trip to Ottawa.

5 0
3 years ago
1/2 (x + 8) - 15 = - 3
seropon [69]

Answer:

4

Because I took the test and got it correct.

5 0
2 years ago
Read 2 more answers
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