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elena55 [62]
3 years ago
8

List the numbers that have 18 as a multiple.

Mathematics
1 answer:
nikklg [1K]3 years ago
8 0
1,18
9,2
6,3
2,9

Thank you for the points :)
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Purple Dog Pet Supply Inc. (PDPS) released its annual results and financial statements. Lucia is reading the summary in the busi
Rama09 [41]

Answer:

$35,000

Step-by-step explanation:

The computation of the dividend amount is given below:

As we know that

Dividend Paid = Net income - Retained earnings for current year

where,

Retained earnings for current year = This year - last year

= $500,000 - $425,000

= $75,000

Now

Dividend Paid is  

= $110,000 - $75,000

= $35,000

4 0
2 years ago
A cube has a length, width and height of 6 feet. What is the volume in cubic INCHES?
rodikova [14]

Volume of cube = ( side)^3

Side = 6 feet = 6×12 = 72 inches ( 1ft =12 inch)

Vol. = (72)^3 = 72×72×72= 373248 cubic inches

6 0
3 years ago
Aiuda porfavor es para un examen
Marianna [84]

Answer:

A

Step-by-step explanation:

5 0
2 years ago
Read 2 more answers
a calculator is listed for $110 and is on clearence for 35% off. sales tax is 7%. what is the cost of the calculator
goldfiish [28.3K]

Answer:

$76.51

Step-by-step explanation:

The price after discounting is (1.00 - .35)($110), or 0.65($110) = $71.50.

The price after 7% sales tax has been added in is

(1.00 + 0.07)($71.50) = $76.51.

6 0
3 years ago
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If α and β are the zeros of the quadratic polynomial f(x) = 3x2–4x + 5, find a polynomialwhose zeros are 2α + 3β and 3α + 2β.
Lelechka [254]

Answer:

\boxed{\sf \ \ \ 3x^2-20x+37\ \ \ }

Step-by-step explanation:

Hello,

a and b are the zeros, we can say that

f(x)=3(x^2-\dfrac{4}{3}x+\dfrac{5}{3}) = 3(x-a)(x-b)=3(x-(a+b)x+ab)

So we can say that

a+b=\dfrac{4}{3}\\ab=\dfrac{5}{3}

Now, we are looking for a polynomial where zeros are 2a+3b and 3a+2b

for instance we can write

(x-2a-3b)(x-3a-2b)=x^2-(2a+3b+3a+2b)x+(2a+3b)(3a+2b)\\= x^2-5(a+b)x+6a^2+6b^2+9ab+4ab

and we can notice that

a^2+b^2=(a+b)^2-2ab so

(x-2a-3b)(x-3a-2b)=x^2-5(a+b)x+6[(a+b)2-2ab]+13ab\\= x^2-5(a+b)x+6(a+b)^2+ab

it comes

x^2-5*\dfrac{4}{3}x+6(\dfrac{4}{3})^2+\dfrac{5}{3}

multiply by 3

3x^2-20x+2*16+5=3x^2-20x+37

4 0
3 years ago
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