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3 years ago

FREEE POINTS JUST COMMENT WHATEVER

Mathematics

2 answers:

Law Incorporation [45]3 years ago

6 0

Answer:

you're awesome

Step-by-step explanation:

tysmmm

xxTIMURxx [149]3 years ago

3 0

Step-by-step explanation:

yayayay thx!!!!!!!!!!!!!

You might be interested in

If this sample is representative of the student population of 360 students, about how many students in the school joined three c

kirill115 [55]

Answer:

For 1 club it is 120 students

Step-by-step explanation:

360/3=120

3 0

3 years ago

I HAVE ANOTHER CLASS TODAY AND NEED TO FINISH IT RIGHT NOW (MAYBE 20 MIN MAX) SOMEBODY PLEASE HELP, ME! ANY ANNOYING OR FAKE ANS

lys-0071 [83]

Answer:

|x - 5| = 2

Step-by-step explanation:

Since we are not given a zero on the number line, we do the following:

Average = midpoint between two numbers on the number line

For this number line,

Average = 3 + 7 ÷ 2

Average = 5

Next we find how many units away are each number from the middle:

3 is 2 units away from 5

7 is 2 units away from 5

Units away = 2

Let's use the formula:

|x - average| = Units away

Substitute values into equation

|x - 5| = 2

Now we solve

Solve for x over the integers:

|x - 5| = 2

Split the equation into two possible equations:

x - 5 = 2 or x - 5 = -2

Add 5 to both sides:

x = -5 + 5 = 2 + 5 or x - 5 + 5 = -2 + 5

Answer:

x = 7 or x = 3

LOOK AT THE GRAPH AND NUMBER LINE

5 0

2 years ago

Which of the following rational functions is graphed below?

vampirchik [111]

Answer:

The correct option is D.

i.e.

$f\left(x\right)=\frac{1}{x\left(x+4\right)}$ is the correct option.

The correct graph is shown in attached figure.

Step-by-step explanation:

Considering the function

$f\left(x\right)=\frac{1}{x\left(x+4\right)}$

$\mathrm{Domain\:of\:}\:\frac{1}{x\left(x+4\right)}\::\quad \begin{bmatrix}\mathrm{Solution:}\:&\:x$

$\mathrm{Range\:of\:}\frac{1}{x\left(x+4\right)}:\quad \begin{bmatrix}\mathrm{Solution:}\:&\:f\left(x\right)\le \:-\frac{1}{4}\quad \mathrm{or}\quad \:f\left(x\right)>0\:\\ \:\mathrm{Interval\:Notation:}&\:(-\infty \:,\:-\frac{1}{4}]\cup \left(0,\:\infty \:\right)\end{bmatrix}$