The solution set of the equation x^2 + 2x - 48 = 0 is x = -1 ± 7
<h3>How to determine the solution set of the equation?</h3>
The equation is given as:
x^2 + 2x - 48 = 0
A quadratic equation is represented as:
ax^2 + bx + c = 0
By comparing both equations, we have
a = 1, b = 2 and c = -48
The solution of the quadratic equation is then calculated using
x = (-b ± √(b^2 - 4ac))/2a
Substitute values for a, b and c in the above equation
x = (-2 ± √(2^2 - 4 * 1 * -48))/2 * 1
This gives
x = (-2 ± √196)/2
Evaluate the square root of 196
x = (-2 ± 14)/2
Divide through by 2
x = -1 ± 7
Hence, the solution set of the equation x^2 + 2x - 48 = 0 is x = -1 ± 7
Read more about quadratic equation at:
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Answer:
R = 12
L = 84
Step-by-step explanation:
R + L =96
L = 7R
R = 1R
L = 7R
1 R + 7R = 8R
R = 12
L = 84
hope it helps,
Answer:b
Step-by-step explanation:idk
In a parallogram the two angles on the same side ( Angle T and Angle C) equal 180 degrees
So we have 8x +29 + 2x +11 = 180
combine the like terms:
10x + 40 = 180
Subtract 40 from each side:
10x = 140
Divide each side by 10:
X = 140 /10
X = 14
Now we have X, replace X into the equation for angle C
2(14) +11 = 28 + 11 = 39 degrees
