The solution set of the equation x^2 + 2x - 48 = 0 is x = -1 ± 7
<h3>How to determine the solution set of the equation?</h3>
The equation is given as:
x^2 + 2x - 48 = 0
A quadratic equation is represented as:
ax^2 + bx + c = 0
By comparing both equations, we have
a = 1, b = 2 and c = -48
The solution of the quadratic equation is then calculated using
x = (-b ± √(b^2 - 4ac))/2a
Substitute values for a, b and c in the above equation
x = (-2 ± √(2^2 - 4 * 1 * -48))/2 * 1
This gives
x = (-2 ± √196)/2
Evaluate the square root of 196
x = (-2 ± 14)/2
Divide through by 2
x = -1 ± 7
Hence, the solution set of the equation x^2 + 2x - 48 = 0 is x = -1 ± 7
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