Answer:
(2,3)
If you have any questions about the way I solved it, don't hesitate to ask ÷)
Answer:
d
Step-by-step explanation:
Using the Cosine rule to find ∠ A
cosA = 
= 
= 
= 
, then
∠ A = 
( ) ≈ 84.9° ( to 1 dec. place )
We start at 62 Fahrenheit. And every hour we drop two degrees. We want to know how long it took for the temperature to drop to 40 Fahrenheit.
If one hour passed, then the temperature dropped two degrees.
If two hours passed, then the temperature dropped 4 degrees.
See the pattern? We can define this as 2h. Where h represents time in hours.
We subtract 2h from 62.
We can write this as a function. F(h) = 62 - 2h.
Where F is the temperature in Fahrenheit. And h is the hour(s).
Now that we have the formula, let's plug in the value 40 Fahrenheit to see how long it took for the temperature to drop to 40 degrees.
40 = 62 - 2h
Subtract 62 from each side
-22 = -2h
Divide both sides by 2
h = 11
So, it took 11 hours for the temperature to drop to 40 Fahrenheit.
Answer:
Step-by-step explanation:
Given that angle A is in IV quadrant
So A/2 would be in II quadrant.
sin A = -1/3
cos A = 
(cos A is positive since in IV quadrant)
Using this we can find cos A/2
Answer:
Mia: 90 and Isabella: 30
Step-by-step explanation:
Mia: 60 x 0.5 (50%) is 30
Isabella: 60 x 1.5 (150%) is 90
