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Bingel [31]
2 years ago
5

If there are 21 ladybugs how many bumblebees?​

Mathematics
1 answer:
fenix001 [56]2 years ago
5 0

Answer:

I need the rest of the question to answer

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John needs to divide the sample in half once the number of bacteria has reached 1000. How many hours after the initial time must
Reil [10]

Answer:

Option A

Step-by-step explanation:

The complete question is attached here

The rate of increase of bacterial population  be K

As we know

Y = Y_0 * e^{kT}

where Y is the final population. In this case it is 1000

K is the rate of increase of population i.e 3 times per hour

T is the time in hours

Y0 is the initial population = 5

Substituting the given values, we get -

1000 = 5 *e^{3*T}\\200 = e^{3*T}

Taking log on both sides, we get -

ln 200 = ln e^{3T}

2.718 * 2.301 = 3T

T = 2.084 hours

hence, option A is correct

8 0
3 years ago
9. What does "piece + piece = total” mean?
Mama L [17]
Answer
1/2 + 1/2 = 1.

8 0
3 years ago
Harry was given an assignment. He had 42 days to get 336 tasks done at work.
OLEGan [10]
Harry needs to use division to find how many tasks he need to do each day. Harry needs to do 336÷42 = 8.
8 0
2 years ago
A bag contains six real diamonds and five fake diamonds if one diamonds is pick what the odds a real diamond is pick
Yuliya22 [10]
6/11 or about 55%

To put into a fraction the total is the denominator and the 6 would be the numerator as it is the real diamond then divide the numerator by the denominator move your decimal two places round as needed
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3 years ago
Read 2 more answers
Please help!!! the question is in the picture above— this is geometry
Serga [27]

Use the co‐interior rule, corresponding angle rule, alternate angle rule and vertical opposite angle rule to solve the question above.

angle G5 = angle K1 reason : corresponding angles

angle J1 = angle H3 reason: vertical opposite angles

angle J2 = angle K4 reason: vertical opposite angles

angle G5 = angle K4 reason: co‐ interior angles

angle F6 = angle K4 reason: alternate angle

8 0
2 years ago
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