Describe its graph. 4

The scores of Tim’s first four math tests are 82%, 90%, 78%, and 100%. If Tim wants to

Crank

82+ 90+78+100 = 350
Tim wants to have a test average of 90% on all of his 6 tests then
90 x 6 = 540

540 - 350 = 190

 the average of Tim’s next two tests = 190 / 2 = 95

answer
average of Tim’s next two tests must be 95

5 0

4 years ago

SOMEONE PLZ HELP ME WITH 10 and 8!!!!!

Allisa [31]

Answer:

10. $23.75^{o}$

8. $34.76^{o}$

Step-by-step explanation:

10. each step is 36, so i added it twice to get 72.

then add 16 twice = 32

this gives us two sides to our triangle.

We can now use tan since we know opp and adj

tan 32/72 = .44

arctan = 23.75

8. since we again know the opposite and adjacent sides to the angle e are trying to find we can use tan again.

tan 12.5/18 = .694

arctan= 34.76

5 0

3 years ago

111111111111111111 anwser

wel

Answer:

111111111111111111

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers

Mark lives in a state that charges him 6.1% income tax on his federal taxable income. If his federal taxable income is $79,400,

AysviL [449]

Answer:

D. 4.843,40

Step-by-step explanation:

The total amount is 79.400 dollars and that is the one to charge with the income tax.

Remembe that 6,1%=0,061 and this is easier to multiply

Income tax= taxable income*income tax

With our numbers

Income tax=79.400*0,061

=4.843,40

Thats the state income tax that Mark has to pay

7 0

3 years ago

A computer retail store has 1414 personal computers in stock. A buyer wants to purchase 33 of them. Unknown to either the retail

Lorico [155]

Answer:

a) 364 ways

b) 45.33% probability that exactly one of the computers will be defective.

c) 54.67% probability that at least one of the computers selected is defective.

Step-by-step explanation:

The computers are chosen without replacement, so we use the hypergeometric distribution to solve this question.

Hypergeometric distribution:

The probability of x sucesses is given by the following formula:

$P(X = x) = h(x,N,n,k) = \frac{C_{k,x}*C_{N-k,n-x}}{C_{N,n}}$

In which:

x is the number of sucesses.

N is the size of the population.

n is the size of the sample.

k is the total number of desired outcomes.

Combinations formula:

$C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

In this question:

14 computers, so N = 14.

3 defective, so k = 3.

3 will be purchesed, so n = 3.

A) In how many different ways can the 3 computers be chosen?

3 from a set of 14. So

$C_{14,3} = \frac{14!}{3!(14-3)!} = 364$

364 ways

B) What is the probability that exactly one of thecomputers will be defective?

This is P(X = 1).

$P(X = 1) = h(1,14,3,3) = \frac{C_{3,1}*C_{11,2}}{C_{14,3}} = 0.4533$

45.33% probability that exactly one of the computers will be defective.

C) What is the probability that at least one of the computers selected is defective?

Either none is, or at least one is. The sum of the probabilities of these events is 1. So

$P(X = 0) + P(X \geq 1) = 1$

We want $P(X \geq 1)$ . Then

$P(X \geq 1) = 1 - P(X = 0)$

In which

$P(X = 0) = h(0,14,3,3) = \frac{C_{3,0}*C_{11,3}}{C_{14,3}} = 0.4533$

$P(X \geq 1) = 1 - P(X = 0) = 1 - 0.4533 = 0.5467$

54.67% probability that at least one of the computers selected is defective.

5 0

3 years ago

Describe its graph. 4 – 5x > 19