The sum of the interior triangles in a triangle is 180, so if we add all the angle measures together, we should get 180. Therefore, we can make an equation like this,
![110-2x+x+50+5x-40=180](https://tex.z-dn.net/?f=110-2x%2Bx%2B50%2B5x-40%3D180)
Simplify this.
![4x+120=180](https://tex.z-dn.net/?f=4x%2B120%3D180)
![4x=60](https://tex.z-dn.net/?f=4x%3D60)
![x=15](https://tex.z-dn.net/?f=x%3D15)
Now we can find each angle measure.
![110-2x](https://tex.z-dn.net/?f=110-2x)
![110-2(15)](https://tex.z-dn.net/?f=110-2%2815%29)
![110-30](https://tex.z-dn.net/?f=110-30)
![80](https://tex.z-dn.net/?f=80)
![x+50](https://tex.z-dn.net/?f=x%2B50)
![15+50](https://tex.z-dn.net/?f=15%2B50)
![65](https://tex.z-dn.net/?f=65)
![5x-40](https://tex.z-dn.net/?f=5x-40)
![5(15)-40](https://tex.z-dn.net/?f=5%2815%29-40)
![75-40](https://tex.z-dn.net/?f=75-40)
![35](https://tex.z-dn.net/?f=35)
So the angle labeled
is the largest angle in the triangle.
First, Rico walked for 3/10 of a mile which is 30/100 of a mile.
Hen, Rico walked for 24/100 of a mile.
Then you add 24/100 and 30/100. 24+30/100 which is 54/100.
Answer=54/100 of a mile
Answer:
$0.64
Step-by-step explanation:
Unit price is the cost of a single metre of ribbon
5.12/8=0.64
Answer:
10.77m
Step-by-step explanation:
4^2 +10^2=c^2
16+100=116
![\sqrt{116 }](https://tex.z-dn.net/?f=%20%5Csqrt%7B116%20%7D%20)
=10.77
a.
×
A
b.
×
A
c.
A
The LED which would glow brightest is LED C with the greatest current and voltage
The LED which would be the most dim is LED B with low voltage and consequently low current.
<h3>How to determine the current</h3>
The formula for finding current
I = V/R
Where v = voltage
R = resistance
A. V = 12V
R = 4. 7 + 15 = 19. 7 kΩ = 19700 Ω in series
![I = \frac{12}{19700}](https://tex.z-dn.net/?f=I%20%3D%20%5Cfrac%7B12%7D%7B19700%7D)
×
A
B. V = 9V
R = 4. 7 + 1 = 4. 7 kΩ = 4700Ω in series
![I = \frac{12}{4700}](https://tex.z-dn.net/?f=I%20%3D%20%5Cfrac%7B12%7D%7B4700%7D)
×
A
C. V= 12V
1/R =
=
× ![10^-3](https://tex.z-dn.net/?f=10%5E-3)
R =
= 310. 56 Ω
![I = \frac{12}{310. 56}](https://tex.z-dn.net/?f=I%20%3D%20%5Cfrac%7B12%7D%7B310.%2056%7D)
A
It is important to note that the brightness of a bulb depends on both current and voltage depending on whether the bulb it is in parallel or series.
The LED which would glow brightest is LED C with the greatest current and voltage
The LED which would be the most dim is LED B with low voltage and consequently low current.
Learn more about Ohms law here:
brainly.com/question/14296509
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