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3 years ago

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In the one pully system when you move the mass from the 20 cm mark to the 15 cm mark, it moves 5 cm. How far did you pull the st

ring. Question 1 options: 5 cm 10 cm 15 cm 20 cm

1 answer:

drek231 [11]3 years ago

4 0

Answer:

5 cm

Explanation:

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Delvig [45]

The correct option is A. the isobaric process represented by the PV diagram

<h3>What is isobaric process?</h3>

An Isobaric method is a thermodynamic revolution taking place at consistent pressure. The period isobaric has been derived from the Greek words “iso” and “baros” indicating equal intimidation.
As such, the continued pressure is obtained when the importance is expanded or acquired. This basically neutralizes any pressure change due to the transfer of heat.

In an isobaric procedure, when the heat is transferred to the system some work is done. Nevertheless, there is even a change in the internal energy of the system.
This additionally means that no amounts as in the first law of thermodynamics evolve zero.

To learn more about isobaric process, refer to:

brainly.com/question/13040268

#SPJ9

5 0

2 years ago

A force is required for any change in an object's motion to occur.<br><br> True<br> False

sertanlavr [38]

Answer:

True

Explanation:

an object in motion stays in motion unless acted upon by another force

7 0

3 years ago

Read 2 more answers

Salmon often jump waterfalls to reach their breeding grounds. Starting downstream, 2.33 m away from a waterfall 0.488 m in heigh

Ulleksa [173]

Answer:

5.68 m/s

Explanation:

The motion of the salmon is the same as a projectile: it is launched with an initial speed $u$ at an angle of $\theta=38^{\circ}$ above the horizontal.

The motion of the salmon consists of two indipendent motion:

- Along the horizontal direction, it is a uniform motion with constant velocity

$v_x = u cos \theta$

So that the distance travelled is

$d=v_x t = u cos \theta t$ (1)

- Along the vertical direction, it is a uniformly accelerated motion with constant acceleration downward, so the vertical displacement is

$y = u sin \theta t - \frac{1}{2}gt^2$ (2)

where g is the acceleration of gravity.

We know the following:

- The horizontal distance travelled by the salmon to reach the waterfall is

d = 2.33 m

- The vertical distance travelled is the height of the waterfall,

y = 0.488 m

From (1) we get:

$t=\frac{d}{u cos \theta}$

And substituting into (2), we can solve the equation to find t, the time at which the salmon reaches the waterfall:

$y = u sin \theta \frac{d}{u cos \theta} - \frac{1}{2}gt^2 = d tan \theta - \frac{1}{2}gt^2\\t = \sqrt{\frac{2(d tan \theta - y)}{g}}=\sqrt{\frac{2(2.33 tan 38^{\circ}-0.488)}{9.81}}=0.521 s$

And then, we can use eq.(1) again to find the initial speed, u:

$u=\frac{d}{cos \theta t}=\frac{2.33}{cos(38^{\circ})(0.521)}=5.68 m/s$

5 0

3 years ago

1. What net force is required to accelerate a car at a rate of 2 m/s2 if the car has a mass of 3,000 kg?

nataly862011 [7]

Answer:

Net force required to accelerate the car is 6000 N

Explanation:

Force is calculated by the equation, F = Mass × Acceleration

This is based on Newton's Second Law of Motion which states that the force acting on an object is its mass times the acceleration of the object.

Here, mass = 3000 kg and acceleration = 2 m/s²

⇒ Force = Mass × Acceleration

= 3000 × 2 = 6000 N

⇒ F = 6000 N

⇒ M = 3000 kg

⇒ a = 2 m/s²

7 0

3 years ago

A gold wire has a cross-sectional area of 1.0 cm^2 and a resistivity of 2.8 × 10^-8 Ω ∙ m at 20°C. How long would it have to be

Karo-lina-s [1.5K]

Answer:

Length, l = 3.57 meters

Explanation:

It is given that,

Area of cross-section of gold wire, $A=1\ cm^2=0.0001\ m^2$

Resistivity of gold wire, $\rho=2.8\times 10^{-8}\ \Omega-m$

Resistance, R = 0.001 ohms

Resistance in terms of length and area is given by :

$R=\rho \dfrac{l}{A}$

$l=\dfrac{RA}{\rho}$

$l=\dfrac{0.001\times 0.0001}{2.8\times 10^{-8}}$

l = 3.57 meters

So, the length of the wire is 3.57 meters. Hence, this is the required solution.

4 0

3 years ago