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Alexxx [7]
2 years ago
5

If the given ordered pair equal then find value of x and y(3x+5)=(x+2)and (4y+7)= (y+3)​

Mathematics
1 answer:
Yanka [14]2 years ago
7 0

Answer:

3x+5 =x+2

3x-x=2-5

2x= –3

x=-3/2

4y+7=y+3

4y–y =3-7

3y=–4

y= —4/3

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if polygon MAST with coordinates M(-3,-1), A(-3,2),S (-1,3) and t (1,1) is reflected across x=-3, then which of the following co
Nookie1986 [14]

Let 'a' be the point and 'A' be the reflection of point 'a' through line x= -3

we know, (a+A)/2 (mid point of line aA) should lie on line x= -3

so by using this, we calculate vertices of reflected shape of MAST, we get

(-3,-1), (-3,2),(-5,3) and (-7,1)


3 0
3 years ago
Read 2 more answers
Don’t answer if you don’t know !!
DochEvi [55]

Answer:

72 sides

Step-by-step explanation:

The sum of the angles of a polygon with n sides is (n−2) × 180

Since the polygon is regular, we can divide by the number of sides to find the measure of each angle (n−2) × 180 / n

Each angle is equal to 175

(n−2) × 180 / n = 175

Multiply each side by n

(n-2)180 = 175n

Distribute

180n -360 = 175n

Subtract 180n from each side

180n-180n-360 = 175n-180n

-360 = -5n

Divide each side by -5

-360/-5 =-5n/-5

72 = n

There are 72 sides

3 0
2 years ago
Read 2 more answers
Find the area of the shaded region
Alex777 [14]

∆BOC is equilateral, since both OC and OB are radii of the circle with length 4 cm. Then the angle subtended by the minor arc BC has measure 60°. (Note that OA is also a radius.) AB is a diameter of the circle, so the arc AB subtends an angle measuring 180°. This means the minor arc AC measures 120°.

Since ∆BOC is equilateral, its area is √3/4 (4 cm)² = 4√3 cm². The area of the sector containing ∆BOC is 60/360 = 1/6 the total area of the circle, or π/6 (4 cm)² = 8π/3 cm². Then the area of the shaded segment adjacent to ∆BOC is (8π/3 - 4√3) cm².

∆AOC is isosceles, with vertex angle measuring 120°, so the other two angles measure (180° - 120°)/2 = 30°. Using trigonometry, we find

\sin(30^\circ) = \dfrac{h}{4\,\rm cm} \implies h= 2\,\rm cm

where h is the length of the altitude originating from vertex O, and so

\left(\dfrac b2\right)^2 + h^2 = (4\,\mathrm{cm})^2 \implies b = 4\sqrt3 \,\rm cm

where b is the length of the base AC. Hence the area of ∆AOC is 1/2 (2 cm) (4√3 cm) = 4√3 cm². The area of the sector containing ∆AOC is 120/360 = 1/3 of the total area of the circle, or π/3 (4 cm)² = 16π/3 cm². Then the area of the other shaded segment is (16π/3 - 4√3) cm².

So, the total area of the shaded region is

(8π/3 - 4√3) + (16π/3 - 4√3) = (8π - 8√3) cm²

7 0
1 year ago
Ill Give brainliest To whoever can answer this please .ASAP . Thanks-Rin
marusya05 [52]

Answer: The answer is c

Explanation:

6 0
3 years ago
Help me with this text please
saw5 [17]
I think the boxes must be filled with
1/3 and -1/5.
3 0
3 years ago
Read 2 more answers
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