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3 years ago

HELP ASAP ILL GIVE U 5 stars

Mathematics

1 answer:

jek_recluse [69]3 years ago

7 0

Answer:

x = 1 . 14

Step-by-step explanation:

5x + 7 + 2x + 1

5x + 2x + 7 + 1

= 7x + 8

= x = 8 / 7

x = 1.1 4

Hope this answer helps you :)

Have a great day

Mark brainliest

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22 pts for this question plz help

victus00 [196]

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3 years ago

A tank contains 250 liters of fluid in which 40 grams of salt is dissolved. Brine containing 1 gram of salt per liter is then pu

VashaNatasha [74]

Answer:

$A(t)=250-210e^{-\frac{t}{50}}$

Step-by-step explanation:

We are given that

Volume,V=250 L

Mass of salt=m=40 g

Brine containing 1 g per liter

Pumped into the tank at the rate=5 L/min

We have to find the number A(t) of grams of salt in the tank at time t.

Rate of change of salt in the tank

$\frac{dA}{dt}=$ Rate in-Rate out

Rate in=5 L/min

Rate out= $\frac{A}{250}\times 5=\frac{A}{50}$ L/min

$\frac{dA}{dt}=5-\frac{A}{50}=\frac{250-A}{50}$

$\int \frac{50dA}{250-A}=\int dt$

$-50ln(250-A)=t+C$

Using the formula

$\int \frac{dx}{x}=ln x$

A=40 and t=0

$-50ln(250-40)=0+C$

$-50ln(210)=C$

Substitute the value

$-50ln(250-A)=t-50ln(210)$

$-50ln(250-A)+50ln(210)=t$

$50ln\frac{210}{250-A}=t$

$t=50ln\frac{210}{250-A}$

$\frac{t}{50}=ln\frac{210}{250-A}$

$\frac{210}{250-A}=e^{\frac{t}{50}$

$\frac{250-A}{210}=e^{-\frac{t}{50}}$

$250-A=210e^{-\frac{t}{50}}$

$A(t)=250-210e^{-\frac{t}{50}}$

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4 years ago

Un automovilista conduce hacia el norte durante 35.0 minutos a 23.61 m/s y ¿Cuál es su desplazamiento?

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3 years ago

What is the sum of the reciprocal of 1/-13 and the reciprocal of -1/2

murzikaleks [220]

Answer:

-15

Step-by-step explanation:

1/-13

The reciprocal is

$1/ 1/-13$

Because of the law of indices,

We'll have $1 * -13$

= -13.

-1/2

The reciprocal is

1 ÷ -1/2

Because of the law of indices,

We'll have $1 * -2$

= -2

Therefore, the sum would be -13 + (-2) which would be equals to -15.

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3 years ago

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olya-2409 [2.1K]

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Step-by-step explanation:

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3 years ago

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