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Sliva [168]
3 years ago
10

Figure ABCD is transformed to figure A′B′C′D′:

Mathematics
1 answer:
Ilia_Sergeevich [38]3 years ago
6 0

Answer:

D. <C'D'A'

Step-by-step explanation:

Given that figure ABCD is transformed to figure A′B′C′D′, therefore the angles of ABCD would be congruent to the corresponding angles of A′B′C′D′.

<CDA corresponds to <C'D'A'. Therefore:

<CDA = <C'D'A'

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Determine between which consecutive integers the real zeros of fw=x^3-2 are located
USPshnik [31]

Answer:

the answer for this question is A

3 0
4 years ago
A cuboid has 3 different sized faces. The areas of 2 of the faces are 84cm2and 56cm2. The volume of the cuboid is 672cm3. Find t
Elenna [48]

Answer:

Length: 12 cm

Width: 8 cm

Height; 7 cm

Step-by-step explanation:

We are told that the areas of 2 of the faces are 84cm² and 56cm².

Now, the side faces are 4 in total with 2 each having same areas.

Thus, it means they would have the same height.

Let's find the highest common factor between 84cm² and 56cm².

The highest number that can be divide each equally is 7.

Thus;

12 × 7 = 84 cm²

8 × 7 = 56 cm²

This means, the bottom part will measure 12 cm by 8 cm.

Thus, the complete measurement is;

Length: 12 cm

Width: 8 cm

Height; 7 cm

Let's check if it will give us a Volume equal to that given.

Thus;

Volume = 12 × 8 × 7 = 672 cm²

This is same as that given and so our dimensions are correct.

7 0
3 years ago
Write an equation that represents “Eight more than the quotient of a number and two is fourteen.”
seropon [69]

Answer:

I think it's supposed to be 8x+2=14

5 0
4 years ago
3. The following sets are not equal - An (BUC) and AU(BnC) Construct a universe U and non-empty sets A, B, and C so that the abo
yarga [219]

Answer:

1.U={1,2,3,4,5}

A={2}

B={2,3}

C={4,5}

2.U={1,2,3,4}

A={1,2}

B={2,3}

C={4}

Step-by-step explanation:

We are given that A\cap (B\cup C) and A\cup (B\cap C)

are different sets

1.We have to construct a universe set U and non empty sets A,B and C so that above set in fact the same

Suppose U={1,2,3,4,5}

A={2}

B={2,3}

C={4,5}

B\cap C=\phi

B\cup C={2,3,4,5}

A\cap (B\cup C)={2}\cap{2,3,4,5}={2}

A\cup (B\cap C)={2}\cup\phi={2}

Hence, A\cap (B\cup C)=A\cup (B\cap C)

2.We have to construct a universe set U and non empty sets A,B and C so that  above sets are in fact different

Suppose U={1,2,3,4}

A={1,2}

B={2,3}

C={4}

B\cap C=\phi

B\cup C={2,3,4}

A\cup (B\cap C)={1,2}\cup \phi={1,2}

A\cap (B\cup C)={1,2}\cap {2,3,4}={2}

Hence, A\cap (B\cup C)\neq A\cup (B\cap C)

3 0
3 years ago
PLEASE HELP!!! K Is the midpoint of JL Find JK,LK and JL
Naya [18.7K]

Answer:

6x+1 = 8x - 7

8 = 2x

x = 4

JK = 6*4+1 = 25

KL = 8*4 - 7 = 25

3 0
3 years ago
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