Answer:
8 vans
7 buses
Step-by-step explanation:
Let there be "b" buses
and "v" vans
Since 7 people is the capacity of vans, the total capacity is
7v
Also, since 25 people is the capacity of 1 bus, the total capacity is
25b
In total 231 people, so we can write our first equation as:
7v + 25b = 231
Now, we know there are 15 vehicles (bus + vans) in total, so we can write our 2nd equation as:
v + b = 15
Now, we solve for v and b. Let's solve the 2nd equation for v and substitute that into 1st and solve for b first:
v + b = 15
v = 15 - b
Now,
Hence, there are 7 buses
Since 15 vehicles in total, the number of vans is:
15 - 7 = 8 vans
So,
8 vans
7 buses
Answer:
0.0032
The complete question as seen in other website:
There are 111 students in a nutrition class. The instructor must choose two students at random Students in a Nutrition Class Nutrition majors Academic Year Freshmen non-Nutrition majors 17 18 Sophomores Juniors 13 Seniors 18 Copy Data. What is the probability that a senior Nutrition major and then a junior Nutrition major are chosen at random? Express your answer as a fraction or a decimal number rounded to four decimal places.
Step-by-step explanation:
Total number of in a nutrition class = 111 students
To determine the probability that the two students chosen at random is a junior non-Nutrition major and then a sophomore Nutrition major, we would find the probability of each of them.
Let the probability of choosing a junior non-Nutrition major = Pr (j non-N)
Pr (j non-N) = (number of junior non-Nutrition major)/(total number students in nutrition class)
There are 13 number of junior non-Nutrition major
Pr (j non-N) = 13/111
Let the probability of choosing a sophomore Nutrition major = Pr (S N-major)
Pr (S N-major)= (number of sophomore Nutrition major)/(total number students in nutrition class)
There are 3 number of sophomore Nutrition major
Pr (S N-major) = 3/111
The probability that the two students chosen at random is a junior non-Nutrition major and then a sophomore Nutrition major = 13/111 × 3/111
= 39/12321
= 0.0032
Answer:
x=9
Step-by-step explanation:
81 is the product of -9 & -9. -9-9=-18. Therefore, (x-9)^2=0, and you get that x=9.
Split up the interval [0, 8] into 4 equally spaced subintervals:
[0, 2], [2, 4], [4, 6], [6, 8]
Take the right endpoints, which form the arithmetic sequence
where 1 ≤ <em>i</em> ≤ 4.
Find the values of the function at these endpoints:
The area is given approximately by the Riemann sum,
where 
; so the area is approximately
where we use the formulas,
