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zaharov [31]
3 years ago
11

What is 5,684.505 in expanded form?

Mathematics
1 answer:
nikdorinn [45]3 years ago
7 0
The Answer:y=5684.505
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PLEASE HELP!!! A group has at most $140 to spend on an event space. The inequality 15h + 40 140 represents the cost to rent the
Zielflug [23.3K]

9514 1404 393

Answer:

  h ≤ 6 2/3

Step-by-step explanation:

The inequality is presumed to be ...

  15h +40 ≤ 140

  15h ≤ 100

  h ≤ 6 2/3

__

The graph shows h ≥ 0, because the inequality is only reasonable for h ≥ 0.

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2 years ago
Luca has a book collection of 95 books. She has read 3/5 of the books in her collection. If Luca reads 12 more books this summer
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Answer:

68

Step-by-step explanation:

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3 years ago
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Which is the difference of 21 1/4 - 18 2/4? A:2 1/4. B:2 2/4. C:2 3/4. D:3 1/4.
seropon [69]

Answer:

2 3/4 C

Step-by-step explanation:

(21+\frac{1}{4})-(18+\frac{2}{4})\\=21-18+\frac{1}{4} -\frac{2}{4} \\=3-\frac{1}{4} \\=\frac{12-1}{4} \\=\frac{11}{4} \\=2\frac{3}{4} \\or\\21\frac{1}{4} -18\frac{2}{4} \\=\frac{85}{4} -\frac{74}{4} \\=\frac{85-74}{4} \\=\frac{11}{4} \\=2\frac{3}{4}

3 0
3 years ago
If the cost of a bat and a baseball combined is $1.10 and the bat costs 41.00 more than the ball, how much is the ball?
shepuryov [24]

Step-by-step explanation:

7 0
3 years ago
A psychological experiment was conducted to investigate the length of time (time delay) between the administration of a stimulus
aleksklad [387]

Answer:

The P-value of this sample is 0 and is less than the significance level (0.05), so the effect is significant and the null hypothesis is rejected.

As there is significant evidence to reject H_0: \mu= 1.6, we can say that there is significant evidence to claim that the mean time delay for the hypothetical population of all persons who may be subjected to the stimulus differs from 1.6 seconds.

The significance level for this test is 0.05.

Step-by-step explanation:

In this case, we want to prove if there is significant evidence that the mean differs from 1.6 seconds. That is the same as having evidence to reject the the hypothesis H_0:\mu= 1.6 (the null hypothesis always have the equal sign).

We have to test the null hypothesis

H_0:\mu= 1.6

The significance level for this test is 0.05

Calculation of the t-statistic:

t=\frac{M-\mu}{s/\sqrt{n}} =\frac{2.2-1.6}{0.57/\sqrt{36}} =\frac{0.6}{0.063}= 9.47

If we look up in a t-table for t=9.47 and df=(36-1)=35, we get this value appears with a probability of zero. A large number like that is very unlikely to happen.

The P-value of this sample is 0 and is less than the significance level (0.05), so the effect is significant and the null hypothesis is rejected.

As there is significant evidence to reject H_0: \mu= 1.6, we can say that there is significant evidence to claim that the mean time delay for the hypothetical population of all persons who may be subjected to the stimulus differs from 1.6 seconds.

6 0
3 years ago
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