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3 years ago

PLZZZ HELP ME ITS DUE TODAY AT 11:59, HELPPPP

Mathematics

2 answers:

Andrew [12]3 years ago

8 0

Answer:

1. 135

2. 21

3.-10

Step-by-step explanation:

kirill [66]3 years ago

4 0

Answer:

1) . Divide that number by 12 months

1620/12 = 135

2) 3 x 7 = 21

21 pounds lost

3) 0 - 4 - 4 - 4 + 2 = -10 points

hope this helps :)

Step-by-step explanation:

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Answer:

1. The expected pay-out on each policy is 250 * 1/90 + 12000 * 1/100 + 17000 * 1/400 = $165. So that's what the premium would have to be in order to get a profit of 0.

2. The profit per policy is the premium the company receives minus the expected payout = 350 - 165 = $185.

3. The expected profit on 375 policies would be 375 * 185 = $69375

Step-by-step explanation:

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3 years ago

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Slav-nsk [51]

Answer:

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3 years ago

What is the factor to change pounds to kilograms

aev [14]

Answer:

1 pounds is equal to 4535 kilograms.

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3 years ago

What is the product?

RSB [31]

Answer:

15a^5b^15

Step-by-step explanation:

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3 years ago

Read 2 more answers

Each year, all final year students take a mathematics exam. It is hypothesised that the population mean score for this test is 1

Yuri [45]

Answer:

90% confidence interval for the population mean test score is [95.40 , 106.59]

Step-by-step explanation:

We are given that the population mean score for mathematics test is 115. It is known that the population standard deviation of test scores is 17.

Also, a random sample of 25 students take the exam. The mean score for this group is 101.

The, pivotal quantity for 90% confidence interval for the population mean test score is given by;

P.Q. = $\frac{Xbar-\mu}{\frac{\sigma}{\sqrt{n} } }$ ~ N(0,1)

where, X bar = sample mean = 101

$\sigma$ = population standard deviation

n = sample size = 25

So, 90% confidence interval for the population mean test score, $\mu$ is ;

P(-1.6449 < N(0,1) < 1.6449) = 0.90

P(-1.6449 < $\frac{Xbar-\mu}{\frac{\sigma}{\sqrt{n} } }$ < 1.6449) = 0.90

P(-1.6449 * $\frac{\sigma}{\sqrt{n} }$ < ${Xbar-\mu}$ < 1.6449 * $\frac{\sigma}{\sqrt{n} }$ ) = 0.90

P(X bar - 1.6449 * $\frac{\sigma}{\sqrt{n} }$ < $\mu$ < X bar + 1.6449 * $\frac{\sigma}{\sqrt{n} }$ ) = 0.90

90% confidence interval for $\mu$ = [ X bar - 1.6449 * $\frac{\sigma}{\sqrt{n} }$ , X bar + 1.6449 * $\frac{\sigma}{\sqrt{n} }$ ]

= [ 101 - 1.6449 * $\frac{17}{\sqrt{25} }$ , 10 + 1.6449 * $\frac{17}{\sqrt{25} }$ ]

= [95.40 , 106.59]

Therefore, 90% confidence interval for the population mean test score is [95.40 , 106.59] .

7 0

3 years ago