Answer:
Total time taken by walking, running and cycling = 22 minutes.
Step-by-step explanation:
Let the speed of walking = x
As given,
The distance of walking = 1
Now,
As 
⇒ Time traveled by walking = 
Now,
Given that - He runs twice as fast as he walks
⇒Speed of running = 2x
Also given distance traveled by running = 1
Time traveled by running = 
Now,
Given that - he cycles one and a half times as fast as he runs.
⇒Speed of cycling =
(2x) = 3x
Also given distance traveled by cycling = 1
Time traveled by cycling = 
Now,
Total time traveled = Time traveled by walking + running + cycling
=
+
+ 
= 
If he cycled the three mile , then total time taken =
+
+
= x
Given,
He takes ten minutes longer than he would do if he cycled the three miles
⇒x + 10 = 
⇒
⇒
⇒x =
= 12
⇒x = 12
∴ we get
Total time traveled by walking + running + cycling =
min
Answer:
<u><em>−125a^(11)</em></u>
Step-by-step explanation:
<u><em>(−5a^(2)3a^(5) Then you solve</em></u>
<u><em>=−125a^(11)</em></u>
Answer:
Y are you making us do the test question you should have been payin attention in class
Step-by-step explanation:
Answer:
b = 12 and c = 5
Step-by-step explanation:
For them to be congruent, the triangles must be congruent by HL, so c+44 = 5b - 11 and b + 34 = 10c - 4. From the first equation, we get that c = 5b - 55. We can substitute this into the second equation and get: b + 34 = 10(5b-55) - 4 = 50b -554 -> 49b =588 -> b = 12. We use this to solve for c: c = 5b -55 = 5(12) - 55 = 60 - 55 = 5. Therefore, b = 12 and x = 5.
I changed up my solution (sorry for the careless mistake), but I hope this helps! :)
A parallel lines never cross like this: I I
Perpendicular lines Cross at 90%: + or x for example.
I hope I helped.