Question

(45x-7)4x=57 solve this and ill make out with you

Answer 1

Answer:

After solving $(45x-7)4x=57$ we get $\mathbf{x=0.645 \ or \ x = -0.490}$

Step-by-step explanation:

We need to solve the equation: $(45x-7)4x=57$

Solving:

$(45x-7)4x=57$

Multiply 4x with terms inside the bracket

$180x^2-28x=57$

$180x^2-28x-57=0$

We need to solve above equation to find value of x

Using quadratic formula for finding value of x: $x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}$

We have a=180, b=-28 and c=-57

$x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}\\x=\frac{-(-28)\pm\sqrt{(-28)^2-4(180)(-57)}}{2(180)}\\x=\frac{28\pm\sqrt{784+41040}}{360}\\x=\frac{28\pm\sqrt{41824}}{360}\\x=\frac{28\pm204.51}{360}\\x=\frac{28+204.51}{360} \ or \ x=\frac{28-204.51}{360}\\x=0.645 \ or \ x = -0.490$

Values of x are $\mathbf{x=0.645 \ or \ x = -0.490}$

So, After solving $(45x-7)4x=57$ we get $\mathbf{x=0.645 \ or \ x = -0.490}$