Answer:
We are 95% confident that the percent of executives who prefer trucks is between 19.43% and 33.06%
Step-by-step explanation:
We are given that in a group of randomly selected adults, 160 identified themselves as executives.
n = 160
Also we are given that 42 of executives preferred trucks.
So the proportion of executives who prefer trucks is given by
p = 42/160
p = 0.2625
We are asked to find the 95% confidence interval for the percent of executives who prefer trucks.
We can use normal distribution for this problem if the following conditions are satisfied.
n×p ≥ 10
160×0.2625 ≥ 10
42 ≥ 10 (satisfied)
n×(1 - p) ≥ 10
160×(1 - 0.2625) ≥ 10
118 ≥ 10 (satisfied)
The required confidence interval is given by

Where p is the proportion of executives who prefer trucks, n is the number of executives and z is the z-score corresponding to the confidence level of 95%.
Form the z-table, the z-score corresponding to the confidence level of 95% is 1.96







Therefore, we are 95% confident that the percent of executives who prefer trucks is between 19.43% and 33.06%
3(2a-5) = 12-7a
6a-15=12-7a
6a+7a=12+15
13a= 27
27=3c-3(6-2c)
27=3c-18+6c
27+18=3c+6c
45=9c
C=45/9
C=5
6c-8-2c=-16
6c-2c=-16+8
4c=-8
C=-8/4
C=-2
Answer:
(B)
Step-by-step explanation:
we know that standard equation of parabola y²= 4x or x² = 4y .
So option (B) is correct .
Hope it's helpful
Answer:$0.25 per apple
$0.30 per orange
Step-by-step explanation:
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people
The answer is an average rate of change of 110 more dollars in her account per week. You find this by first subtracting the starting amount of 250 from the end amount of 800 that equals 550. then you divide that number by five, the number of weeks, to get the average rate of change.