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devlian [24]
3 years ago
12

quick question heh.... How do you know when to use the Secant-Secant Prodict Theorem or the Secant-Tangent Product Theorem?

Mathematics
1 answer:
Vaselesa [24]3 years ago
6 0
You use the theorem you can apply to your problem.

If there is no tangent, the secant-tangent product theorem cannot apply.
If you don't have two secants, the secant-secant product theorem cannot apply.
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Which of the sets of ordered pairs represents a function? (4 points)
vovikov84 [41]

Answer: D, neither A nor B

Step-by-step explanation: In a function, the x (the input) cannot repeat in the given set of ordered pairs. In Set A, 2 repeats in the third and fourth ordered pairs. In Set B, 9 repeats in the third and fourth ordered pairs as well.

3 0
2 years ago
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In a Gallup poll of randomly selected​ adults, 66% said that they worry about identity theft. For a group of 1013​ adults, the m
Lady_Fox [76]

Answer: 669

Step-by-step explanation:

Given, In a Gallup poll of randomly selected​ adults, 66% said that they worry about identity theft.

i.e. The proportion of adults said that they worry about identity theft. (p) = 0.66

Sample size : n= 1013

Then , Mean for the sampling distribution of sample proportion  = <em>np</em>

= (1013) × (0.66)

= 668.58 ≈ 669  [Round to the nearest whole number]

Hence, the mean of those who do not worry about identify theft is closest to​ 669 .

7 0
2 years ago
Solve the following proportion for y.<br> y/9 = 8/11<br> Round your answer to the nearest tenth.
jek_recluse [69]
Answer: 6.5

6.5/11 ≈ 8/11
8 0
2 years ago
What is the product of (4x-7)(4x+7)?
miskamm [114]
(a+b)(a-b)=a^2 - b^2
so

<span>(4x-7)(4x+7) = 16x^2 - 49

answer
</span>16x^2 - 49
6 0
3 years ago
Given sin theta= 6/11 and sec theta &lt; 0, find cos theta and tan theta.
bekas [8.4K]

Answer: option a.

Step-by-step explanation:

By definition, we know that:

cos^2(\theta)=1-sen^2(\theta)\\\\tan(\theta)=\frac{sin(\theta)}{cos(\theta)}

Substitute sin(\theta)=\frac{6}{11} into the first equation, solve for the cosine and simplify. Then, you obtain:

cos(\theta)=\±\sqrt{1-(\frac{6}{11})^2}\\\\cos(\theta)=\±\sqrt{\frac{85}{121}}\\\\ cos(\theta)=\±\frac{\sqrt{85}}{11}

As sec\theta then cos\theta:

cos(\theta)=-\frac{\sqrt{85}}{11}

Now we can find tan\theta:

tan\theta=\frac{\frac{6}{11}}{-\frac{\sqrt{85}}{11}}\\\\tan\theta=-\frac{6\sqrt{85}}{85}

4 0
3 years ago
Read 2 more answers
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