Answer:
The average value of
over the interval
is
.
Step-by-step explanation:
Let suppose that function
is continuous and integrable in the given intervals, by integral definition of average we have that:
(1)
(2)
By Fundamental Theorems of Calculus we expand both expressions:
(1b)
(2b)
We obtain the average value of
over the interval
by algebraic handling:
![F(5) - F(3) +[F(3)-F(-2)] = 40 + (-30)](https://tex.z-dn.net/?f=F%285%29%20-%20F%283%29%20%2B%5BF%283%29-F%28-2%29%5D%20%3D%2040%20%2B%20%28-30%29)



The average value of
over the interval
is
.
the 4 because it's in the hundred place value
I THINK THAT"S HOW YOU DO IT, BUT YOU KNOW JUST TRYING TO HELP YOU :)
Answer:
M = [0; -1]
Step-by-step explanation:
Midpoint of the segment AB: M = [0; -1]
<span> 5×-(3+9)
Substitute 6 for x
5(6)-(3+9)
Add 9 to 3
5(6)-12
Multiply 5 by 6
30-12
Final Answer: 18</span>
Answer:
x-1=y or y+1=x
Step-by-step explanation:
I think thats right,