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ElenaW [278]
3 years ago
10

Triangle RST is diated to form triangle R'S'T with the scale factor of 3.5. If RT=8 what is the length of R'T

Mathematics
1 answer:
shepuryov [24]3 years ago
3 0

Answer:

R'T = 28

Step-by-step explanation:

Dilation is one of the methods used in transformation. It is a process in which the size of a given object or shape is either increased or decreased by a scale factor.

In the given question, the length of RT was increased by the scale factor, so that;

R'T = RT x scale factor

      = 8 x 3.5

      = 28

R'T = 28

Therefore, the length of R'T is equal to 28.

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The average value of a function f over the interval [−2,3] is −6 , and the average value of f over the interval [3,5] is 20. Wha
Xelga [282]

Answer:

The average value of f over the interval [-2,5] is \frac{10}{7}.

Step-by-step explanation:

Let suppose that function f is continuous and integrable in the given intervals, by integral definition of average we have that:

\frac{1}{3-(-2)} \int\limits^{3}_{-2} {f(x)} \, dx = -6 (1)

\frac{1}{5-3} \int\limits^{5}_{3} {f(x)} \, dx = 20 (2)

By Fundamental Theorems of Calculus we expand both expressions:

\frac{F(3)-F(-2)}{3-(-2)} = -6

F(3) - F(-2) = -30 (1b)

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We obtain the average value of f over the interval [-2, 5] by algebraic handling:

F(5) - F(3) +[F(3)-F(-2)] = 40 + (-30)

F(5) - F(-2) = 10

\frac{F(5)-F(-2)}{5-(-2)} = \frac{10}{5-(-2)}

\bar f = \frac{10}{7}

The average value of f over the interval [-2,5] is \frac{10}{7}.

4 0
3 years ago
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Answer:

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Step-by-step explanation:

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<span> 5×-(3+9)
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Step-by-step explanation:

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