A because if you count 4 units to the right you get 3 and if you go up 2 units you get 5 and you in the positive part of the graph so it’ll be A
Answer:
The pattern is min-zero-max-zero-min, which is the pattern for a cosine function of the form y = acos(x) + k, but is reflected over the x-axis (so a < 0).
The amplitude is |a|, so a = –1 and |a| = 1.
The midline is exactly between the max and the min, y = (6 + 8)/2 = 7, so k = 7.
The equation is y = –cos(x) + 7.
hope it helps :)
mark brainliest!!
We know that
(1/4) hour---------> 0.25 hour
if the pump r<span>ecirculate 75 gallons of water in -------------> 0.25 hour
X </span>gallons of water in-----------------------------------------> 1 hour
X=75/0.25----------> x=300 gallons /hour
the answer is 300 gallons /hour
Using proportions, it is found that there would be 500,000 mites.
- This question is solved by <em>proportions</em>, using a rule of three.
- Each dust mite has a length of
m. How many dust mites could there be in a line of
m long?
The <em>rule of three</em> is:
1 dust mite -
m.
x dust mites -
m
Applying cross multiplication:
![2.5 \times 10^{-4}x = 1.25 \times 10^2](https://tex.z-dn.net/?f=2.5%20%5Ctimes%2010%5E%7B-4%7Dx%20%3D%201.25%20%5Ctimes%2010%5E2)
![x = \frac{1.25 \times 10^2}{2.5 \times 10^{-4}}](https://tex.z-dn.net/?f=x%20%3D%20%5Cfrac%7B1.25%20%5Ctimes%2010%5E2%7D%7B2.5%20%5Ctimes%2010%5E%7B-4%7D%7D)
![x = 500000](https://tex.z-dn.net/?f=x%20%3D%20500000)
There would be 500,000 mites.
A similar problem is given at brainly.com/question/24372153