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3 years ago

Help please thank you!!!

Mathematics

1 answer:

Usimov [2.4K]3 years ago

3 0

Answer:

0.1. the first onw us correct by the way !!! edgenty SUCKSSS!

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What is the area of triangle DEF?

FrozenT [24]

Answer:

$A=2\sqrt{14}\ units^2$

Step-by-step explanation:

we know that

Heron's Formula is a method for calculating the area of a triangle when you know the lengths of all three sides.

$A=\sqrt{s(s-a)(s-b)(s-c)}$

where

a, b and c are the length sides of triangle

s is the semi-perimeter of triangle

we have

$a=5\ units,b=6\ units,c=3\ units$

<em>Find the semi-perimeter s </em>

s= $\frac{5+6+3}{2}=7\ units$

Find the area of triangle

$A=\sqrt{7(7-5)(7-6)(7-3)}$

$A=\sqrt{7(2)(1)(4)}$

$A=\sqrt{56}\ units^2$

simplify

$A=2\sqrt{14}\ units^2$

3 0

2 years ago

You and two friends share 7 cookies equally. How many cookies do you each get?

Ivahew [28]

4 cookies because three divided by seven equals three hope I helped

5 0

3 years ago

Read 2 more answers

Please answer the question on the image attached

belka [17]

Y= -2+21
This is because the slope needs to be the negative reciprocal of 1/2 so the slope is -2 then you take the point (5,11) and plug that an the -2 into y=m(x)+b and you solve for b. In the end you get 21

3 0

3 years ago

The quadrilateral ABCD has area of 58 in2 and diagonal AC = 14.5 in. Find the length of diagonal BD if AC ⊥ BD.

azamat

Answer:

(look in the the Step by step)

Step-by-step explanation:

When the diagonals of a quadrilateral are perpendicular, the area of that quadrilateral is half the product of their lengths.

.. A = (1/2)*d₁*d₂

Substituting the given information, this becomes

.. 58 in² = (1/2)*(14.5 in)*d₂

.. 2*58/14.5 in = d₂ = 8 in

The length of diagonal BD is 8 in.

4 0

2 years ago

You are dealt two cards successively (without replacement) from a shuffled deck of 52 playing cards. Find the probability that t

icang [17]

Answer:

The probability that the first card is a Heart and the second card is a Spade is 0.064.

Step-by-step explanation:

A standard deck of 52 cards is shuffled and two cards are drawn without replacement.

The denominations of the cards are as follows:

Spades (S) = 13

Hearts (H) = 13

Diamonds (D) = 13

Clubs (C) = 13

Compute the probability of selecting a Heart first as follows:

$P(H)=\frac{13}{52}=0.25$

Compute the probability of selecting a Spade second as follows:

$P(S)=\frac{13}{51}=0.255$

Since the two cards are selected without replacement the second draw is independent of the other.

Then the probability that the first card is a Heart and the second card is a Spade is:

$P(1st\ H\cap 2nd\ S)=P(H)\times P(S)$

$=0.25\times 0.255\\=0.06375\\\approx 0.064$

Thus, the probability that the first card is a Heart and the second card is a Spade is 0.064.

4 0

3 years ago