Please help this is due today!!
1 answer:
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For this, you would’ve needed a calculator:
Because this is a right triangle, you can apply SOH CAH TOA (sin, cosin, and tangent)
You have the hypotenuse, so now you need to figure out where the angle is in relation to x and y (one at a time though).
45 degrees is opposite from x, so you would use sin (SOH) because you have the opposite and hypotenuse. This looks like:
sin(45) = opposite/6(sqrt)2
So now you want to solve for the opposite, so do 6(sqrt)2 multiplied by sin(45). Which gets you 6.
For y, you want to find adjacent so use cosin. To solve, it’s going to look like 6(sqrt)2 • cos(45) which gets you 6.
Because this is a right triangle, you can apply SOH CAH TOA (sin, cosin, and tangent)
You have the hypotenuse, so now you need to figure out where the angle is in relation to x and y (one at a time though).
45 degrees is opposite from x, so you would use sin (SOH) because you have the opposite and hypotenuse. This looks like:
sin(45) = opposite/6(sqrt)2
So now you want to solve for the opposite, so do 6(sqrt)2 multiplied by sin(45). Which gets you 6.
For y, you want to find adjacent so use cosin. To solve, it’s going to look like 6(sqrt)2 • cos(45) which gets you 6.
