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kakasveta [241]
2 years ago
14

I have two questions

Mathematics
2 answers:
Elza [17]2 years ago
8 0

Answer:

1. 40%

2. 56.25%

Step-by-step explanation:

1. N% of 15 = 6

N/100 x 15 =6

N = (6 × 100)/15

N = 40

2.N% of 32 = 18

N/100 x 32 = 18

N = (18 x 100) /32

N= 56.25

MA_775_DIABLO [31]2 years ago
6 0

Answer for question 1 is Percentage Calculator: 6 is what percent of 15? = 40.

Answer for question 2 is What is 18 percent (calculated percentage %) of number 32? Answer: 5.76.

hope it helps. Please mark me Brainleist please.

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A bacteria culture starts with 400 bacteria and grows at a rate proportional to its size. After 4 hours, there are 9000 bacteria
Kaylis [27]

Answer:

A) The expression for the number of bacteria is P(t) = 400e^{0.7783t}.

B) After 5 hours there will be 19593 bacteria.

C) After 5.55 hours the population of bacteria will reach 30000.

Step-by-step explanation:

A) Here we have a problem with differential equations. Recall that we can interpret the rate of change of a magnitude as its derivative. So, as the rate change proportionally to the size of the population, we have

P' = kP

where P stands for the population of bacteria.

Writing P' as \frac{dP}{dt}, we get

\frac{dP}{dt} = kP.

Notice that this is a separable equation, so

\frac{dP}{P} = kdt.

Then, integrating in both sides of the equality:

\int\frac{dP}{P} = \int kdt.

We have,

\ln P = kt+C.

Now, taking exponential

P(t) = Ce^{kt}.

The next step is to find the value for the constant C. We do this using the initial condition P(0)=400. Recall that this is the initial population of bacteria. So,

400 = P(0) = Ce^{k0}=C.

Hence, the expression becomes

P(t) = 400e^{kt}.

Now, we find the value for k. We are going to use that P(4)=9000. Notice that

9000 = 400e^{k4}.

Then,

\frac{90}{4} = e^{4k}.

Taking logarithm

\ln\frac{90}{4} = 4k, so \frac{1}{4}\ln\frac{90}{4} = k.

So, k=0.7783788273, and approximating to the fourth decimal place we can take k=0.7783. Hence,

P(t) = 400e^{0.7783t}.

B) To find the number of bacteria after 5 hours, we only need to evaluate the expression we have obtained in the previous exercise:

P(5) =400e^{0.7783*5} = 19593.723 \approx 19593.  

C) In this case we want to do the reverse operation: we want to find the value of t such that

30000 = 400e^{0.7783t}.

This expression is equivalent to

75 = e^{0.7783t}.

Now, taking logarithm we have

\ln 75 = 0.7783t.

Finally,

t = \frac{\ln 75}{0.7783} \approx 5.55.

So, after 5.55 hours the population of bacteria will reach 30000.

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Let's solve your equation step-by-step.

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</span></span></span>Step 1: Simplify both sides of the equation.

<span><span>2<span>(<span>x−6</span>)</span></span>=<span>3<span>(<span>x+3</span>)

</span></span></span><span>Simplify: (Show steps)

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</span></span>Step 2: Subtract 3x from both sides.

<span><span><span><span>2x</span>−12</span>−<span>3x</span></span>=<span><span><span>3x</span>+9</span>−<span>3x

</span></span></span><span><span><span>−x</span>−12</span>=9

</span>Step 3: Add 12 to both sides.

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</span>Step 4: Divide both sides by -1.

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</span></span>Answer:

<span>x=<span>−<span>21</span></span></span>
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