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3 years ago

What does 32 3/4 turn into

Mathematics

2 answers:

kotykmax [81]3 years ago

4 0

Answer:

131/4

Step-by-step explanation:

you multiply the denominator by 32 (which is 4) and you add it to the numerator)

32 x 4 = 128

128 + 3 = 131

so your answer is 131/4

and your the answer for your equation 32 3/4 - 12 1/2

32 3/4 − 12 1/2

= 131/4 − 25/2

= 81/4

= 20 1/4

4vir4ik [10]3 years ago

3 0

Do the denominator x the number in front + the numerator to turn into an improper fractions. Those r easier to work w

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PLEASE HELP ASAPPPP!

Gemiola [76]

Answer:

3 7/16 cups

Step-by-step explanation:

5 1/2 x 5/8 = 55/16 = 3 7/16

5 0

3 years ago

Consider the following equation. f(x, y) = y3/x, P(1, 2), u = 1 3 2i + 5 j (a) Find the gradient of f. ∇f(x, y) = Correct: Your

BaLLatris [955]

$f(x,y)=\dfrac{y^3}x$

a. The gradient is

$\nabla f(x,y)=\dfrac{\partial f}{\partial x}\,\vec\imath+\dfrac{\partial f}{\partial y}\,\vec\jmath$

$\boxed{\nabla f(x,y)=-\dfrac{y^3}{x^2}\,\vec\imath+\dfrac{3y^2}x\,\vec\jmath}$

b. The gradient at point P(1, 2) is

$\boxed{\nabla f(1,2)=-8\,\vec\imath+12\,\vec\jmath}$

c. The derivative of $f$ at P in the direction of $\vec u$ is

$D_{\vec u}f(1,2)=\nabla f(1,2)\cdot\dfrac{\vec u}{\|\vec u\|}$

It looks like

$\vec u=\dfrac{13}2\,\vec\imath+5\,\vec\jmath$

so that

$\|\vec u\|=\sqrt{\left(\dfrac{13}2\right)^2+5^2}=\dfrac{\sqrt{269}}2$

Then

$D_{\vec u}f(1,2)=\dfrac{\left(-8\,\vec\imath+12\,\vec\jmath\right)\cdot\left(\frac{13}2\,\vec\imath+5\,\vec\jmath\right)}{\frac{\sqrt{269}}2}$

$\boxed{D_{\vec u}f(1,2)=\dfrac{16}{\sqrt{269}}}$

7 0

3 years ago

What is the solution to the system of equations? Use the substitution method.

BabaBlast [244]

The answer is:
4x+2y=11} 4x+2y=11} x=2-2y
x-2=-2y } x+2y=2 } x=2-2(-3/6)
x=2-(-6/6)
4(2-2y)+2y=11 x=2-(-1)
8-8y+2y=11 x=3
8-6y=11
-6y=11-8
-6y=3/-6
y=-3/6=-1/2

So for my opinion the solution is A.(3,-1/2)

4 0

3 years ago

List the next three numbers for the sequence: 25, 75, 300, 1500, ...

ELEN [110]

Answer: 2000

Step-by-step explanation:

4 0

3 years ago

How do you find the slope of the line that goes<br> through the points (-5, 6) and (7,-6)?

strojnjashka [21]

Answer:

Step-by-step explanation:

$slope=\frac{y_{2}-y_{1}}{x_{2}-x_{1}}\\\\=\frac{-6-6}{7-[-5]}\\\\=\frac{-12}{7+5}\\\\=\frac{-12}{12}\\\\=-1$

5 0

3 years ago