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GenaCL600 [577]
3 years ago
8

PLZ HELPP I BEGG BRANLIEST PROVIDED.PLZZZZZZZZ

Mathematics
2 answers:
dmitriy555 [2]3 years ago
8 0

Answer:

30 3/8 or 30.375 m^3

Step-by-step explanation:

I'm not sure if they want the decimal or fraction, so I gave both.

1/4 = 0.25

1/2 = 0.5

3 * 2.25 * 4.5 = 30.375 m^3

ikadub [295]3 years ago
7 0

Answer:

30.375

Step-by-step explanation:

Volume of a rectangular prism = Length times Width times Height

If width = 3, length = 2 and 1/4 and height = 4 and 1/2

Then volume = 3*2\frac{1}{4} *4\frac{1}{2}

3*2\frac{1}{4} *4\frac{1}{2} =\frac{243}{8}

Therefore the volume of the prism is 243/8 or 30.375

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Ann spent $7.74 on oranges. If each orange costs $0.36 per pound, how many pounds of oranges did Ann buy?
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Q20-23 with steps pls
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20: Let x be the amount of money. If this amount is shared between 8 people, each person will get x/8 dollars. But there actually are 6 people, so everyone is getting x/6 dollars. We know that this difference results in 30 dollars more, so we have

\dfrac{x}{6}=\dfrac{x}{8}+30 \iff \dfrac{x}{6}-\dfrac{x}{8}=30

Rearrange the left hand side as

\dfrac{4x-3x}{24}=30

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21: Let M and J be the number of marbles owned by Mike and Judy, respectively. At the beginning, we have

M=3J+11

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M+J+18=93 \iff M+J=75 \iff M=75-J

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75-J=3J+11 \iff 4J=64 \iff J=16

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22: Let x,y,z be the number of $10, $20 and $50 coupon, respectively. We're given:

\begin{cases}x=2y+3\\z=\frac{1}{2}y\\x+y+z=38\end{cases}&#10;We can write the third equation by substituting the expressions for x and z:&#10;[tex]x+y+z=(2y+3)+y+\left(\dfrac{1}{2}y\right)=38

Rearrange as follows:

(2y+3)+y+\left(\dfrac{1}{2}y\right)=38 \iff \dfrac{7}{2}y=35 \iff 7y=70 \iff y=10

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x=2\cdot 10+3=23,\quad z=\dfrac{1}{2}\cdot 10=5

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23\cdot 10+10\cdot 20+5\cdot 50=230+200+100=530

23:  a) In order to find the first three terms of the sequence, you just need to plug n=1,2,3:

a_1=4\cdot 1+3=7,\quad a_2=4\cdot 2+3=11,\quad a_3=4\cdot 3+3=15

b) We have

a_r = 4r+3=71 \iff 4r=68 \iff r=\dfrac{68}{4}=17

c) 105 is a term of the sequence if and only if there exists an integer k such that

a_k=4k+3=105 \iff 4k = 102 \iff k=\dfrac{102}{4}=25.5

So, 105 is not a term of the sequence.

8 0
4 years ago
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