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Natali5045456 [20]
3 years ago
6

15 POINTS PLEASE HELP!!!!!

Mathematics
1 answer:
Nesterboy [21]3 years ago
8 0

Answer:

<h2>A new car worth $25,000 is depreciating (loses value) in value by $1,250 per year. Determine how many years will it take for the car to be worth $8,500.</h2>

<h3>ಠ︵ಠwait what that's not 15 points liar but it's okay and at least it helps✅(≧▽≦)</h3>

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what problem could happen if judges only used whole numbers instead of decimals to keep scores? What problems might arise?
Bas_tet [7]
The outcome wouldn't be 100% correct
8 0
3 years ago
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(25) Points please help will pick someone has the brainliest if right!
dem82 [27]

Answer:

D) 80

Step-by-step explanation:

Your answer is 80 because to find median you must Add up all of the numbers and divide by the number of numbers in the data set. The median is the central number of a data set. Arrange data points from smallest to largest and locate the central number. This is the median. Which I did and got 80 Your welcome

Hope this helped if it did plz give me brainiest Thanks <3

6 0
4 years ago
What does ‘x’ equal
Dmitriy789 [7]

Answer:

x=(-9)

Step-by-step explanation:

Step 1: Simplify both sides of the equation.

(−2/3)(9+x)=0

(−2/3)(9)+(−2/3)(x)=0(Distribute)

−6+−2/3x=0

−2/3x−6=0

Step 2: Add 6 to both sides.

−2/3x−6+6=0+6

−2/3x=6

Step 3: Multiply both sides by 3/(-2).

(3−2)*(−2/3x)=(3−2)*(6)

x=−9


6 0
3 years ago
If the population of a particular country is growing at 1.5 % compounded​ continuously, how long will it take the population to
DIA [1.3K]
e^{0.015t}=3
Taking natural logs of both sides, we get
0.015t=ln 3
t = ln 3/0.015 = 73.24

The answer is 73.24 years.
5 0
3 years ago
So confused! I have the answer, but can't understand the explanation. Please help...
andrey2020 [161]
(mx^3+3)*(2x^2+5x+2)-(8x^5+20x^4)=8x^3+6x^2+15x+6 \\ (mx^3*2x^2)+(mx^3*5x)+(mx^3*2)+(3*2x^2)+(3*5x)+(3*2) \\ -8x^5-20x^4=8x^3+6x^2+15x+6\\ \\ 2mx^5+5mx^4+2mx^3+6x^2+15x+6-8x^5-20x^4 \\ =8x^3+6x^2+15x+6 \\ \\ (2m-8) x^{5} +(5m-20) x^{4} +2mx^3+6x^2+15x+6 \\ =8x^3+6x^2+15x+6 \\ \\ (2m-8) x^{5} +(5m-20) x^{4} +(2m-8)x^3=0 \\ (m-4) 2x^{5} +(m-4) 5x^{4} +(m-4)2 x^3=0 \\ (m-4)( 2x^{5} + 5x^{4} +2 x^3)=0 \\ m=4

6 0
3 years ago
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