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Alex_Xolod [135]

3 years ago

6

Two students are reading a novel. Ashley reads 2 pages per day. Carly reads 1 page per day, but she starts early and is already

on page 5. When will the two students read on the
same page?

Ashley:p=2d
Carly:p=d+5

1 answer:

Anestetic [448]3 years ago

8 0

They would on day 4 that they would be on the same page

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A bacterial culture starts with 3000 bacteria and increases to 48,000 after 3 hours, find the doubling time:

STatiana [176]

4

3000 times 2 = 6000
6000 times 2 = 12000
12000 times 2 = 24000
24000 times 2 = 48000

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3 years ago

I’LL MARK BRAINLEST! :)

dem82 [27]

Answer:

9.1

Step-by-step explanation:

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There are 18 streetlights evenly spaced on a

Stells [14]

Answer:

144 streetlights

Step-by-step explanation:

1.5 is equivalent to 1/2

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4 years ago

WILL GIVE BRAINLIEST

IrinaK [193]

Part one:

$x^2-8x=-26$

Rewrite in the form $(x+a)^{2} =b$

$\left(x-4\right)^2=-10$

$\mathrm{For\:}f^2\left(x\right)=a\mathrm{\:the\:solutions\:are\:}f\left(x\right)=\sqrt{a},\:-\sqrt{a}$

Solve $x-4=\sqrt{-10} : x=\sqrt{10} i+4$

Solve $x-4=\sqrt{-10} : x=-\sqrt{10} i+4$

$x=\sqrt{10}i+4,\:x=-\sqrt{10}i+4$

Part two:

$x=\frac{-\left(-8\right)\pm \sqrt{\left(-8\right)^2-4\cdot \:1\cdot \:26}}{2\cdot \:1}$

Simplify $\sqrt{\left(-8\right)^2-4\cdot \:1\cdot \:26}}: 2\sqrt{10} i$

$=\frac{-\left(-8\right)\pm \:2\sqrt{10}i}{2\cdot \:1}$

Separate solutions

$x_1=\frac{-\left(-8\right)+2\sqrt{10}i}{2\cdot \:1},\:x_2=\frac{-\left(-8\right)-2\sqrt{10}i}{2\cdot \:1}$

$\frac{-(-8)+2\sqrt{10}i }{2*1} :4+\sqrt{10}i$

$\frac{-(-8)+2\sqrt{10}i }{2*1} :4-\sqrt{10}i$

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3 years ago

2(4 - d)= 3(2+d) How can you Find d?

lana66690 [7]

2*4=8
2*d=2d
3*2=6
3*d=3d
Then collect like terms
8-2d=6+3d
2+5d

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