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timofeeve [1]
3 years ago
12

Which number is rational?

Mathematics
2 answers:
Fittoniya [83]3 years ago
7 0

Answer:

last option- square root of 16 is a rational number

V125BC [204]3 years ago
3 0

Answer:

D. Square root of 16

Step-by-step explanation:

Rational numbers are numbers that have simple answers. It is also considered as fractions, Integers, and possible square roots.

- If you chose the square root of 2 = 1.41

- Pi has a value of 3.14, It's not a fraction nor an integer so it's an Irrational number

- Square root of 10 is 3.16

- So Square root of 16 is 4 which is a regular number and a possible square root.

Thank you!

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Plz plz help me on number 15 plz plz help me.
GrogVix [38]
The answer is 30578.33
Just here to help ;)
7 0
3 years ago
In a football or soccer game, you have 22 players, from both teams, in the field. what is the probability of having at least any
Tamiku [17]

We can solve this problem using complementary events. Two events are said to be complementary if one negates the other, i.e. E and F are complementary if

E \cap F = \emptyset,\quad E \cup F = \Omega

where \Omega is the whole sample space.

This implies that

P(E) + P(F) = P(\Omega)=1 \implies P(E) = 1-P(F)

So, let's compute the probability that all 22 footballer were born on different days.

The first footballer can be born on any day, since we have no restrictions so far. Since we're using numbers from 1 to 365 to represent days, let's say that the first footballer was born on the day d_1.

The second footballer can be born on any other day, so he has 364 possible birthdays:

d_2 \in \{1,2,3,\ldots 365\} \setminus \{d_1\}

the probability for the first two footballers to be born on two different days is thus

1 \cdot \dfrac{364}{365} = \dfrac{364}{365}

Similarly, the third footballer can be born on any day, except d_1 and d_2:

d_3 \in \{1,2,3,\ldots 365\} \setminus \{d_1,d_2\}

so, the probability for the first three footballers to be born on three different days is

1 \cdot \dfrac{364}{365} \cdot \dfrac{363}{365}

And so on. With each new footballer we include, we have less and less options out of the 365 days, since more and more days will be already occupied by another footballer, and we can't have two players born on the same day.

The probability of all 22 footballers being born on 22 different days is thus

\dfrac{364\cdot 363 \cdot \ldots \cdot (365-21)}{365^{21}}

So, the probability that at least two footballers are born on the same day is

1-\dfrac{364\cdot 363 \cdot \ldots \cdot (365-21)}{365^{21}}

since the two events are complementary.

8 0
3 years ago
What is the y-intercept of the line 3x-4y=24
Contact [7]

Answer:

(0,-6)

Step-by-step explanation:

3x-4y=24

To find the y intercept, let x =0 and solve for y

3(0) -4y =24

-4y =24

Divide by -4

-4y/-4 = 24/-4

y = -6

The y intercept is

(0,-6)

5 0
3 years ago
Read 2 more answers
Help with math pls mfs pls
Allushta [10]

Answer:

pi

Step-by-step explanation:

pi is the way us pi and radius

6 0
3 years ago
Answer to 3,4,5,6,7,8,9,10,11,12 !!
sineoko [7]
3. i=129; j=112
4.k=90;l=116;m=64;n=86
5.o=13;p=78;q=91
6.a=120;b=60;c=140
Can't see #7
You did 8 I believe
9.v=39;w=59;x=121
10.y=59;z=93
11.a=42;b=48;c=132
12.a=60;b=50;c=80;d=100
8 0
3 years ago
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