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Mila [183]
4 years ago
11

Which is the recommended method for reading your math textbook most effectively? a. read, question, summarize, practice b. highl

ight, skim, ask, and review c. preview, read, summarize, and review
Mathematics
1 answer:
Damm [24]4 years ago
4 0

Answer:  a. read, question, summarize, practice

Step-by-step explanation:

This may be subjective, but the most efficient method usually is:

> Read:

Obviously the first step is read, if there is something that you do not understand, keep reading (but take note of all the things that you don't understand), is important that you have a complete overview on the topic that you are studying

> Question:

Now is time to ask about the things that you did not understand in the first read, always when you do not fully understand something, is a good habit to ask about it, this is the best and easiest way to learn.

> Summarize:

Now that you understand all the text (or at least most of it) is the moment to summarize your new knowledge: Write all the new equations that you learned, also write for what they are for, when they can be useful, etc.

This is what you will use to solve exercises, so you should be clear when writing.

> Practice:

This is one of the most important parts, here is where you put in practice your new knowledge. Here you may find some problematic situations where you need to be inventive with your equations, which will allow you to learn new ways to use your equations, so this is a really important step.

So the correct option is A.

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Find the values of the sine, cosine, and tangent for ZA C A 36ft B <br> 24ft
Reptile [31]
<h2>Question:</h2>

Find the values of the sine, cosine, and tangent for ∠A

a. sin A = \frac{\sqrt{13} }{2},  cos A = \frac{\sqrt{13} }{3},  tan A = \frac{2 }{3}

b. sin A = 3\frac{\sqrt{13} }{13},  cos A = 2\frac{\sqrt{13} }{13},  tan A = \frac{3}{2}

c. sin A = \frac{\sqrt{13} }{3},  cos A = \frac{\sqrt{13} }{2},  tan A = \frac{3}{2}

d. sin A = 2\frac{\sqrt{13} }{13},  cos A = 3\frac{\sqrt{13} }{13},  tan A = \frac{2 }{3}

<h2>Answer:</h2>

d. sin A = 2\frac{\sqrt{13} }{13},  cos A = 3\frac{\sqrt{13} }{13},  tan A = \frac{2 }{3}

<h2>Step-by-step explanation:</h2>

The triangle for the question has been attached to this response.

As shown in the triangle;

AC = 36ft

BC = 24ft

ACB = 90°

To calculate the values of the sine, cosine, and tangent of ∠A;

<em>i. First calculate the value of the missing side AB.</em>

<em>Using Pythagoras' theorem;</em>

⇒ (AB)² = (AC)² + (BC)²

<em>Substitute the values of AC and BC</em>

⇒ (AB)² = (36)² + (24)²

<em>Solve for AB</em>

⇒ (AB)² = 1296 + 576

⇒ (AB)² = 1872

⇒ AB = \sqrt{1872}

⇒ AB = 12\sqrt{13} ft

From the values of the sides, it can be noted that the side AB is the hypotenuse of the triangle since that is the longest side with a value of 12\sqrt{13} ft (43.27ft).

<em>ii. Calculate the sine of ∠A (i.e sin A)</em>

The sine of an angle (Ф) in a triangle is given by the ratio of the opposite side to that angle to the hypotenuse side of the triangle. i.e

sin Ф = \frac{opposite}{hypotenuse}             -------------(i)

<em>In this case,</em>

Ф = A

opposite = 24ft (This is the opposite side to angle A)

hypotenuse = 12\sqrt{13} ft (This is the longest side of the triangle)

<em>Substitute these values into equation (i) as follows;</em>

sin A = \frac{24}{12\sqrt{13} }

sin A = \frac{2}{\sqrt{13}}

<em>Rationalize the result by multiplying both the numerator and denominator by </em>\sqrt{13}<em />

sin A = \frac{2}{\sqrt{13}} * \frac{\sqrt{13} }{\sqrt{13} }

sin A = \frac{2\sqrt{13} }{13}

<em>iii. Calculate the cosine of ∠A (i.e cos A)</em>

The cosine of an angle (Ф) in a triangle is given by the ratio of the adjacent side to that angle to the hypotenuse side of the triangle. i.e

cos Ф = \frac{adjacent}{hypotenuse}             -------------(ii)

<em>In this case,</em>

Ф = A

adjacent = 36ft (This is the adjecent side to angle A)

hypotenuse = 12\sqrt{13} ft (This is the longest side of the triangle)

<em>Substitute these values into equation (ii) as follows;</em>

cos A = \frac{36}{12\sqrt{13} }

cos A = \frac{3}{\sqrt{13}}

<em>Rationalize the result by multiplying both the numerator and denominator by </em>\sqrt{13}<em />

cos A = \frac{3}{\sqrt{13}} * \frac{\sqrt{13} }{\sqrt{13} }

cos A = \frac{3\sqrt{13} }{13}

<em>iii. Calculate the tangent of ∠A (i.e tan A)</em>

The cosine of an angle (Ф) in a triangle is given by the ratio of the opposite side to that angle to the adjacent side of the triangle. i.e

tan Ф = \frac{opposite}{adjacent}             -------------(iii)

<em>In this case,</em>

Ф = A

opposite = 24 ft (This is the opposite side to angle A)

adjacent = 36 ft (This is the adjacent side to angle A)

<em>Substitute these values into equation (iii) as follows;</em>

tan A = \frac{24}{36}

tan A = \frac{2}{3}

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3 years ago
How do you write 20,484,163 in expanded form?for 5 grade
Setler [38]
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3 years ago
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Determine whether the lines x+ 7y= −3 and y = 7x + 25 are parallel, perpendicular, or neither. Justify your answer by showing al
Zielflug [23.3K]

Answer:

perpendicular

Step-by-step explanation:

Rewrite the equations

y = (-1/7)x - 3/7 -- L1

y = 7x + 25 -- L2

Slope of L1 x Slope of L2 = -1/7 x 7 = -1

As a result, the two lines are perpendicular

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3 years ago
Will mark brainliest, answer please !!!!
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Answer:

its the first one 3rd one (brainliest please) (hope this helped)

Step-by-step explanation:

your 7s all equal 7^6

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exponent distributes to the 2 so its 7^2 times 3 so its 7^6 which is the same

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Answer:

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Step-by-step explanation:

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