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3 years ago

What is the product of V6 and7/18 in simplest radical form?

Mathematics

1 answer:

likoan [24]3 years ago

6 0

hope this will help u.........

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Is √10 in simplest form?

Veseljchak [2.6K]

3.16227766017

rounded it is 3

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3 years ago

Mike's Bikes charges an initial fee of $10 to rent a bike plus $5 per hour (h) of use. If the total cost (t) can be determined u

Juli2301 [7.4K]

Answer:

It is 3 hrs.

Step-by-step explanation:

because the ten dollars of initial fee takes off the 25 dollars, we have 15 left, and mike's bikes charges $5/hour, so 15/3+=5

6 0

3 years ago

Leilani makes $11 an hour. One week she works 40 hours. How much money did Leilani make that week? A.$51 B.$80 C.$440 D.$800 PLZ

Law Incorporation [45]

440 because 11x40 is 440 that’s how much she’ll make :)

8 0

3 years ago

Read 2 more answers

Find the diagonal of a rectangular frame which measures 77 in. by 36 in.

quester [9]

Answer:

Diagonal of a rectangular frame = 85 inch

Step-by-step explanation:

Given:

Length of rectangle = 77 inch

Width of rectangle = 36 inch

Find:

Diagonal of a rectangular frame

Computation:

Diagonal of a rectangle = √l² + b²

Diagonal of a rectangular frame = √77² + 36²

Diagonal of a rectangular frame = √5,929 + 1,296

Diagonal of a rectangular frame = √7,225

Diagonal of a rectangular frame = 85 inch

7 0

3 years ago

Write out the first few terms of the series Summation from n equals 0 to infinity (StartFraction 2 Over 3 Superscript n EndFract

anyanavicka [17]

Answer:

$\sum\limits_{n=0}^{\infty} \frac{2}{3^n}\frac{(-1)^n}{5^n} = 15/8$

Step-by-step explanation:

The sum you are trying to understand is this.

$\sum\limits_{n=0}^{\infty} \frac{2}{3^n}\frac{(-1)^n}{5^n}$

Remember that in general when you have a geometric series

$\sum\limits_{n = 0}^{\infty} a*r^n$ you have that

$\sum\limits_{n = 0}^{\infty} a*r^n = \frac{a}{1-r}$ and that equality is true as long as $|r| < 1$ .

Therefore here we have

$\sum\limits_{n=0}^{\infty} \frac{2}{3^n}\frac{(-1)^n}{5^n} = \sum\limits_{n=0}^{\infty} 2* \big(\frac{-1}{3*5} \big)^n = \sum\limits_{n=0}^{\infty} 2* \big(\frac{-1}{15} \big)^n$ and $\big|\frac{-1}{15} \big| = \frac{1}{15} < 1$

Therefore we can use the formula and

$\sum\limits_{n=0}^{\infty} 2* \big(\frac{-1}{15} \big)^n = \frac{2}{1-(-1/15)} = \frac{2}{1+1/15} = 30/16 = 15/8$

5 0

3 years ago