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vaieri [72.5K]
4 years ago
14

The playing life of a Sunshine radio is normally distributed with mean LaTeX: \muμ = 600 hours and standard deviation LaTeX: \si

gmaσ = 100 hours. What is the probability that a radio selected at random will last from 600 to 700 hours
Mathematics
1 answer:
Hitman42 [59]4 years ago
8 0

Answer:

The probability that a radio selected at random will last from 600 to 700 hours is 0.3413

Step-by-step explanation:

The playing life of a Sunshine radio is normally distributed

Mean =\mu = 600 hours

Standard deviation =\sigma = 100 hours

We are supposed to find the probability that a radio selected at random will last from 600 to 700 hours i.e.P(600<x<700)

Formula:Z= \frac{x-\mu}{\sigma}

At x = 600

Z= \frac{600-600}{100}

Z=0

P(X

At x = 700

Z= \frac{700-600}{100}

Z=1

P(X

P(600

Hence the probability that a radio selected at random will last from 600 to 700 hours is 0.3413

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A big-screen TV that previously sold for $2,400 has been marked down to $2,040. What is the percent of decrease?
Hitman42 [59]

[~Answer~] (8.):
Heyyy. I'm Avery, and I'm always here to help!

I believe the percent may be 15% ($2,400 - 15% = $2,040)

+++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++

[~Answer Explanation~}:

The percent of the difference is the rate of the difference * 100%

the percent of the difference = .15 * 100% = 15%

since the new price is less than the old price, that is the percent of the decrease.

(See if it'll work): $2,400- 15% = $2,040

And there's your answer <33

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[~Last Messages~}:

<em>Hope this helped you <333
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How many times does 1 and 7/8 go into at least nine but less than 10?
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Should be four times to get in between 9 and 10
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-3.8x - 5.9x = 223.1
katrin2010 [14]

Answer:

x=-23

Step-by-step explanation:

-3.8x-5.9x=223.1

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3x−8 ≤ 23 OR −4x+26≥6 find x
ElenaW [278]

Answer:

3x-8<=23

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Outside a​ home, there is aa 44​-key keypad numbered 11 through 44. The correct sixsix​-digit code will open the garage door. Th
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Answer:

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Step-by-step explanation:

a)  

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ways of forming six-digit arrangements where each position has 4 possibilities (1 to 4)

b)

The probability of entering the correct code on the first try, assuming that the owner does not remember the code is  

1/4096 = 0.000244

5 0
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