Accuplacer question

Given that f(x)=2x+1 and g(x)=-5x+2 slice for f(g(x)) when x=3?

mezya [45]

Answer:

x = -25.

Step-by-step explanation:

If f(x) = 2x + 1, and g(x) = -5x + 2, then f(g(x)) = 2(-5x + 2) + 1 = -10x + 4 + 1 = -10x + 5.

f(g(x)) = -10x + 5, and x = 3.

-10 * 3 + 5

= -30 + 5

= -25.

Hope this helps!

3 0

3 years ago

IM CONFUSED AGAIN- i hate math

allochka39001 [22]

Answer: 1:50

The scale factor is 5/250 = 1/50

3 0

3 years ago

Read 2 more answers

How do you simplify 22.5+7(n-3.4)

Dima020 [189]

the answer is that n=0.185714285714

6 0

3 years ago

Read 2 more answers

Consider the following linear equations. y = 2x + 5 y = 2x - 3 Which statement below if True?

Fantom [35]

Answer:

Option B is correct

Step-by-step explanation:

The equation of a straight line is given as;

y = mx + b

where m is the slope and b is y-intercept

Let’s evaluate the options one after the other;

A. This is wrong as they both have same slope of 2

C. The y-intercepts are not the same

One is 5, the other is -3

D. This is wrong, the line cannot be the same

Option B is correct

The y-intercept of both varies

While 1 is already appreciated, the other is coming back

3 0

3 years ago

Convert 5 square root of a into exponential form?

stich3 [128]

Answer:

The answer is: " $5a^\frac{1}{2}$ " .

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Step-by-step explanation:

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We are asked to convert "5 square root of a" ; into "exponential form".

Note that "5 square root of a" ;

or; " 5 root a " ;

means: " 5 times the {square root of the variable, "a" };

or : " 5 multiplied by the {square root of the variable, "a" }.

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This can be written as: " $5\sqrt{a}$ " .

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Note the following property of exponents:

$\sqrt[n]{a^m} = (\sqrt[n]{a})^m = a^m^n$ .

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So; to write: " √a " ; as an exponent :

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Note:

" $\sqrt{a} = \sqrt[2]{a} = \sqrt[2]{a^1} = (\sqrt[2]{a})^1 = a^\frac{1}{2}$ " .

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So:

" $\sqrt{a} = a^\frac{1}{2}$ " ;

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And:

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" $5\sqrt{a} = 5a^\frac{1}{2}$ " .

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→ The answer is: " $5a^\frac{1}{2}$ " .

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Hope this helps!

Best wishes in your academic endeavors

— and within the "Brainly" community!

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6 0

3 years ago