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balandron [24]
2 years ago
15

Ben and Alyssa play a game in which they earn the same number of points for each goal and lose the same number of points for eac

h penalty. Ben makes 7 goals and 2 penalties, ending the game with 21 points. Alyssa earns 10 goals and 8 penalties and ends the game with -6 points. How much does a penalty cost and how much does a goal give?
Mathematics
1 answer:
Nadya [2.5K]2 years ago
5 0

Answer:

Each goal gives 5 points and a penalty costs 7 points.

Step-by-step explanation:

Let a penalty cost = x points

And a goal gives = y points

Ben makes 7 goals and 2 penalties ending the game with 21 points,

7y - 2x = 21 --------(1)

Alyssa makes 10 goals and 8 penalties ending the game with (-6) points,

10y - 8x = -6

5y - 4x = -3 --------(2)

Equation (1) multiplied by 2, then subtracted from equation (2),

(5y - 4x) - 2(7y - 2x) = -3 - 2(21)

5y - 4x - 14y + 4x = -3 - 42

-9y = -45

y = 5

From equation (1)

7(5) - 2x = 21

35 - 2x = 21

2x = 35 - 21

2x = 14

x = 7

Therefore, each goal gives 5 points and a penalty costs 7 points.

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Truee is right you got it dude
4 0
2 years ago
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Find AB when given angle B 64 degress angle C 75 degrese and side a 19
jeka94

Answer:

about 28

Step-by-step explanation:

you have to use the sine rule = side you know * ( sin of angle opposing the side you want to know / sin of angle opposing the side you know)

AB = 19* (sin 75/ sin ( 180 -75-64) )

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4 0
3 years ago
Write a formula that will yield the nth term of the sequence: 3,-2,-7,-12
RUDIKE [14]

Answer:

-5n + 8

Step-by-step explanation:

<u>1. What is the difference?</u>

  The sequence goes down by 5. This means that the formula will have -5n in it.

<u>2. Work out the term before the first term.</u>

    The first term is 3, and we know that the sequence goes up by 5. So, to get the term before 3 we would add 5.

3 + 5 = 8   Remember, this is positive 8. (+8)

<u>3. Put that term at the end of the equation. </u>

   We have -5n already and we just worked out the term before the first one which is positive 8 - so put that at the end of the equation.

-5n + 8  This is our answer!

Just to prove it works:

<em>Substitute:   n = term</em>

Lets see if we can get the 3rd term which is -7. (n = 3)

-5(3) + 8

-15 + 8 = -7

See, it works!

8 0
3 years ago
For each of the following functions, determine if they are injective. Also determine if theyare surjective. Also determine if th
timurjin [86]

Answer:

Check below

Step-by-step explanation:

1. Definition for intervals

(a,b)=\left \{ x\in\Re : a

2. Functions

1) \Re \rightarrow \Re \\ f(x)=x

Let's perform graph tests.

That's an one to one, injective function. Look how any horizontal line touches that only once. Also, It's a surjective and a bijective one.

2)\Re\geq0\rightarrow\Re , f(x)=x+1\\

Injective, surjective and bijective.

Injective: a horizontal line crosses the graph in one point.

3)f:\Re\geq 0\rightarrow\Re, f(x) = cos(x)

The cosine function is not injective, bijective nor surjective.

4)f:\Re\rightarrow\Re \:f(x)=ex

Since e, is euler number it's a constant. It's also injective, surjective and bijective.

5)  Quite unclear format

6) \:f:\Re\rightarrow(0,\infty), f(x) =ex

Despite the Restriction for the CoDomain, the function remains injective, surjective and therefore bijective.

7) f:\Re\geq 0 \rightarrow  \Re\geq0, f(x) =x^{4}

Not injective nor surjective therefore not bijective too.

8).f:\{-1,2,-3\}}\rightarrow \{1,4,9\}, f(x) =x^{2}

f(-1)=1, f(2)=4, f(-3)=9

Injective (one to one), Surjective,  and Bijective.

10) f:\Re\geq 0\rightarrow [-1,1], f(x)= cos(x)\\-1=cos(x) \therefore x=\pi,3\pi,5\pi,etc.

Surjective.

11.f:R\geq 0[-1,1], f(x) = 0\\

Surjective

12.f: US Citizens→Z, f(x) = the SSN of x.

General function

13.f: US Zip Codes→US States, f(x) = The state that x belongs to.

Surjective

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2 years ago
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Answer:

( x - 3 )( x + 3 ) ( x - 4 )( x + 4)

Step-by-step explanation:

( x^2 - 9 ) ( x^2 - 16 )

( x - 3 )( x + 3 ) ( x - 4 )( x + 4)

Hopefully this helps!

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