Step-by-step explanation:
Solution:
(6xy) × (-3x²y³)
= {6 × (-3)} × {xy × x²y³}
= -18x1+2 y1+3
= -18x³y⁴.
Answer:
<em>Beck actually caught 45 fish</em>
Step-by-step explanation:
<u>System of Equations</u>
We call the following variables:
x = number of fish Ally caught
y = number of fish Beck caught
They caught a total of 75 fish, thus:
x + y = 75 [1]
If Ally had caught twice as much fish as she actually did, and Beck had caught three times as many fish as he actually did, then Ally would have caught 75 fewer fish than Beck, thus:
3y = 2x + 75 [2]
From [1]:
x = 75 - y [3]
Substituting in [2]:
3y = 2(75 - y) + 75
Operating:
3y = 150 - 2y + 75
Simplifying:
5y = 225
Dividing by 5:
y = 45
Beck actually caught 45 fish
If you would like to solve (- 0.5) / (- 0.5) and - 50 / (- 0.5), you can do this using the following few steps:
(- 0.5) / (- 0.5) = 0.5 / 0.5 = 1
- 50 / (- 0.5<span>) = 50 / 0.5 = 50 / (5/10) = 50 / (1/2) = 50 * 2/1 = 100
</span>
The correct results would be: (- 0.5) / (- 0.5) = 1 and - 50 / (- 0.5<span>) = 100.</span>
<span>45n^(5/2) is the answer
</span>
B a counterclockwise rotation about the origin of 90°
under a counterclockwise rotation about the origin
a point ( x , y ) → (- y, x)
figure Q to figure Q'
( 4,2 ) → (- 2, 4 )
(7, 5 ) → (- 5, 7 )
(3, 7 ) → (- 7 , 3 )
(2, 4 ) → (- 4, 2 )
(5, 4 ) → (- 4, 5 )
the coordinates of the original points of the vertices of Q map to the corresponding points on the image Q'
