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Leokris [45]
3 years ago
14

PLEASE HELPPP! TWO DIFFERENT GRAPHS, TWO DIFFERENT QUESTIONS,

Mathematics
1 answer:
timurjin [86]3 years ago
4 0

Answer:

I am not 100%

#1 = C,D,E

#2 = 1/2

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Geometry!! can someone help me with #23 please? it would mean a lot thanks :)
Bogdan [553]

Answer:

yes, they are parallel lines in #23

Step-by-step explanation:

the slope of both lines is -1

7 0
3 years ago
Identify all values, if any, in the data set that would be considered outliers when creating a modified boxplot. 4 5 7 9 10 10 1
matrenka [14]

Answer:

31

Step-by-step explanation:

 

5 0
3 years ago
Q2) The number of people signed up for a bus trip increased from 32 to
Oduvanchick [21]

Answer:

45-32 = 13 / 32 *100= 40.625 round to the nearest percent is 41%

Step-by-step explanation: Brainlest plzzz

5 0
3 years ago
Find an explicit solution of the given initial-value problem. (1 + x4) dy + x(1 + 4y2) dx = 0, y(1) = 0
MissTica

Answer:

a solution is 1/2 *tan⁻¹ (2*y) = - tan⁻¹ (x²) + π/4

Step-by-step explanation:

for the equation

(1 + x⁴) dy + x*(1 + 4y²) dx = 0

(1 + x⁴) dy  = - x*(1 + 4y²) dx

[1/(1 + 4y²)] dy = [-x/(1 + x⁴)] dx

∫[1/(1 + 4y²)] dy = ∫[-x/(1 + x⁴)] dx

now to solve each integral

I₁= ∫[1/(1 + 4y²)] dy = 1/2 *tan⁻¹ (2*y) + C₁

I₂=  ∫[-x/(1 + x⁴)] dx

for u= x² → du=x*dx

I₂=  ∫[-x/(1 + x⁴)] dx = -∫[1/(1 + u² )] du = - tan⁻¹ (u) +C₂ =  - tan⁻¹ (x²) +C₂

then

1/2 *tan⁻¹ (2*y) = - tan⁻¹ (x²) +C

for y(x=1) = 0

1/2 *tan⁻¹ (2*0) = - tan⁻¹ (1²) +C

since tan⁻¹ (1²) for π/4+ π*N and tan⁻¹ (0) for  π*N , we will choose for simplicity N=0 . hen an explicit solution would be

1/2 * 0 = - π/4 + C

C= π/4

therefore

1/2 *tan⁻¹ (2*y) = - tan⁻¹ (x²) + π/4

5 0
3 years ago
PLEASE HURRY
s2008m [1.1K]

Answer:

1.25p

Step-by-step explanation:

p = amount raised last year

amount raised this year = p +(25% of p)

=1 p+0.25p

=p(1+0.25)

=1.25p

8 0
3 years ago
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