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3 years ago

1) Evaluate the following function for x = -7 3x + 10 =

Mathematics

2 answers:

Artyom0805 [142]3 years ago

8 0

x = -7

To find = 3x + 10

= 3(-7) + 10

= -21 + 10

= -11

Answered by GauthMath if you like please click thanks and comment thanks.

krek1111 [17]3 years ago

5 0

Answer:

-11

Step-by-step explanation:

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Simplify the expression.

Maksim231197 [3]

Answer:

6.8x - 5

Step-by-step explanation:

To answer this question I combined like terms:

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2.5x + 4.3x = 6.8x

Then you add the 5 to the end of the expression:

6.8x - 5

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3 years ago

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3 years ago

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3 years ago

The points (−3, r) and (2, 1) lie on a line with slope −2 . Find the missing coordinate r .

SVETLANKA909090 [29]

We can use point slope form to solve for this.

y - 1 = -2(x - 2)
Simplify.
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6 0

4 years ago

Please solve the problem

jek_recluse [69]

Treat the matrices on the right side of each equation like you would a constant.

Let 2X + Y = A and 3X - 4Y = B.

Then you can eliminate Y by taking the sum

4A + B = 4 (2X + Y) + (3X - 4Y) = 11X

==> X = (4A + B)/11

Similarly, you can eliminate X by using

-3A + 2B = -3 (2X + Y) + 2 (3X - 4Y) = -11Y

==> Y = (3A - 2B)/11

It follows that

$X=\dfrac4{11}\begin{bmatrix}12&-3\\10&22\end{bmatrix}+\dfrac1{11}\begin{bmatrix}7&-10\\-7&11\end{bmatrix} \\\\ X=\dfrac1{11}\left(4\begin{bmatrix}12&-3\\10&22\end{bmatrix}+\begin{bmatrix}7&-10\\-7&11\end{bmatrix}\right) \\\\ X=\dfrac1{11}\left(\begin{bmatrix}48&-12\\40&88\end{bmatrix}+\begin{bmatrix}7&-10\\-7&11\end{bmatrix}\right) \\\\ X=\dfrac1{11}\begin{bmatrix}55&-22\\33&99\end{bmatrix} \\\\ X=\begin{bmatrix}5&-2\\3&9\end{bmatrix}$

Similarly, you would find

$Y=\begin{bmatrix}2&1\\4&4\end{bmatrix}$

You can solve the second system in the same fashion. You would end up with

$P=\begin{bmatrix}2&-3\\0&1\end{bmatrix} \text{ and } Q=\begin{bmatrix}1&2\\3&-1\end{bmatrix}$

3 0

3 years ago