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Afina-wow [57]
3 years ago
8

The sum of 5 consecutive odd numbers is 145. What is the third number in this sequence

Mathematics
1 answer:
vredina [299]3 years ago
5 0

Answer: The 3rd number in the sequence is 29.

Step-by-step explanation: What we have is a sequence of “ODD” numbers and they are consecutive, which means they come one after another with regular intervals. We don’t have any of the numbers but we can start by saying ‘let x represent the first number in the sequence’

With this in mind, we can now assume all other four numbers in the sequence. Therefore if the 1st number is x, the 2nd number would be x + 2, and the the 3rd number would be x + 4, 4th number would be x + 6 while the 5th number would be x + 8.

The reason is that, every odd number is an addition of two to the previous odd number. For instance, if you start with 3, the next odd number would be 3+2 (5), and so on.

Therefore we can now write our consecutive odd numbers as follows;

x + (x + 2) + (x + 4) + (x + 6) + (x + 8)

Remember that all the numbers add up to 145. Therefore,

x + x + 2 + x +4 + x + 6 + x + 8 = 145

5x + 20 = 145

Subtract 20 from both sides of the equation

5x = 125

Divide both sides of the equation by 5

x = 25.

The first odd number is 25, which means the 3rd odd number is 25 + 4.

Therefore the 3rd odd number is 29.

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kondor19780726 [428]

Answer:

No real roots

Step-by-step explanation:

Given

7x² + 5x + 1 = 0 ← in standard form

with a = 7, b = 5, c = 1

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Δ = b² - 4ac

• If b² - 4ac > 0 then roots are real and distinct

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• If b² - 4ac < 0 then the roots are not real

Here

b² - 4ac = 5² - (4 × 7 × 1) = 25 - 28 = - 3

Thus the 2 roots are not real

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Hey there!

Palindromes are numbers that can be written the same way backwards, such as 101 and 12321. You're looking for some numbers which are palindromes, and so are their square numbers.

Alright, I'll give you four of those:

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